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2 years ago

46. Order these numbers from least to greatest: 1/2, 0.4, 1/3, 1/5

Mathematics

1 answer:

e-lub [12.9K]2 years ago

4 0

Answer:

1/5, 1/3, 0.4, 1/2

Step-by-step explanation:

1/5 = 0.2

1/3 = 0.33

1/2 = 0.5

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Two Step Equations<br><br> 9=5- 9/3

Alex787 [66]

9=5 -y/3
-5
3=-y/3
cross multiply
1=-y
y=-1

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2 years ago

Joe has eaten 2/5 of a pizza. James has eaten 1/7. How many times more pizza has Joe eaten than James?

11Alexandr11 [23.1K]

First let's make the denominators of the fractions equal.
To do this, we have to find a number which both 5 and 7 divide into.
The smallest number that does this is 35.

2 --> Multiply the numerator by 7
--
5 --> Multiply the denominator by 7 to get 35

= 14/35

1 --> Multiply the numerator by 5
--
7 --> Multiply the denominator by 5 to get 35

= 5/35

Joe has eaten 14/35 and James has eaten 5/35.
14 / 5 = 2.8

<u>Joe has eaten 2.8 (or 2 4/5) times more pizza than James.</u>

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3 years ago

3 3/15 write the fraction as a decimal

daser333 [38]

3.2 . I don't really know how to explain this, but I need to write at least 20 characters to give you my answer.

4 0

3 years ago

Read 2 more answers

The following data represent the monthly phone use, in minutes, of a customer enrolled in a fraud prevention program for the pas

Illusion [34]

Answer:

The answer is "717.25 minutes".

Step-by-step explanation:

In this question first, we arrange the value in ascending order that are:

307,311,321,322,354,363,377,406,425,435,461,464,474,499,505,513,517,534,548

The median is always in an orderly position that is $= \frac{(n+1)}{2}$ .

$\to \frac{(n+1)}{2} = \frac{(20+1)}{2} = 10.5$ position orders

$10^{th} \ and \ 11^{th}$ place an average of observations so, the

$Average = \frac{(425 +435)}{2} = \frac{(860)}{2} =430$

Because as medium stands at 10.5 that median is as below 10 are greater than the level.

$Q_1$ often falls throughout the ordered BELOW average is $= \frac{(n+1)}{2}$ place.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered position

Average $5^{th} \ and \ 6^{th}$ location findings

$Q_1 = \frac{(354+363)}{2} = \frac{(717)}{2}= 358.5$

In $= \frac{(n+1)}{2}$ the ordered place, Q3 always falls ABOVE the median.

$\to \frac{(n+1)}{2} = \frac{(10+1)}{2} = 5.5^{th}$ ordered At median ABOVE

Consequently $Q_3$ falls between $5^{th} \ and \ 6^{th}$ ABOVE the median position

$15^{th}\ and \ 16^{th}$ place average of observations

$\to Q_3 = \frac{(499+505)}{2}=\frac{(1004)}{2} = 502$

$\to IQR = Q_3 - Q_1= 502-358.5= 143.5$

$\to \text{Upper fence} = Q_3 + 1.5 \times IQR= 502 + 1.5 \times 143.5 = 717.25$

4 0

3 years ago

Identify the input and the output given the relation described:

MatroZZZ [7]

The input is the cost or the amount of money Mr. Edward has to pay in order to park. The output is the parking space allotted for every hour that the car is parked.

It could also be that the input is the effort Mr. Edward put in asking for the cost while the output is the information needed by Mr. Edward - the cost of parking per hour.

5 0

3 years ago