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Dmitry_Shevchenko [17]

3 years ago

15

Which two points in the graphed function have an average rate of change of 5?

1 answer:

djverab [1.8K]3 years ago

3 0

Answer:

<h2>D. points A and B</h2>

Step-by-step explanation:

Look at the picture.

$average\ rate=\dfrac{rise}{run}$

$A.\ B\ and\ C\to\dfrac{-3}{-1}=3\\\\B.\ D\ and\ F\to\dfrac{-12}{2}=-6\\\\C.\ C\ and\ E\to\dfrac{-8}{4}=-2\\\\D.\ A\ and\ B\to\dfrac{-5}{-1}=5$

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Pls help me right now

Irina-Kira [14]

Search the question on the internet and ask if which it is out of them both answers and there you go

6 0

3 years ago

Consider triangle ABC. The legs have a length of 5 units each. What is the length of the hypotenuse of the triangle?

Korvikt [17]

Answer:

$5\sqrt{2}$ units.

Step-by-step explanation:

We have been given that two legs of triangle ABC measures 5 units each. We are asked to find the length of the hypotenuse.

We will use Pythagoras theorem to solve for the hypotenuse of triangle ABC.

$\text{Hypotenuse}^2=\text{Leg}^2+\text{Leg}^2$

Substituting our given values in above equation we will get,

$\text{Hypotenuse}^2=5^2+5^2$

$\text{Hypotenuse}^2=25+25$

$\text{Hypotenuse}^2=50$

Upon taking square root of both sides of our equation we will get,

$\text{Hypotenuse}=\sqrt{50}$

$\text{Hypotenuse}=\sqrt{25*2}$

$\text{Hypotenuse}=5\sqrt{2}$

Therefore, the length of hypotenuse of triangle ABC is $5\sqrt{2}$ units.

6 0

3 years ago

Read 2 more answers

Evaluate the expression for x=6<br> 4×+6

alexira [117]

Answer:

30

Step-by-step explanation:

x=6

4 by 6 =24

24 + 6 =30

7 0

3 years ago

Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC

e-lub [12.9K]

Answer:

$DC=\frac{8}{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

$BM^2=AB^2-AM^2$

we have

$AB=5\ units\\AM=x\ units$

substitute

$BM^2=5^2-x^2$

$BM^2=25-x^2$ -----> equation A

<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

$BM^2=BC^2-MC^2$

we have

$BC=7\ units\\MC=AC-AM=(9-x)\ units$

substitute

$BM^2=7^2-(9-x)^2$

$BM^2=49-(81-18x+x^2)$

$BM^2=49-81+18x-x^2$

$BM^2=-x^2+18x-32$ ----> equation B

equate equation A and equation B

$-x^2+18x-32=25-x^2$

solve for x

$18x=25+32\\18x=57\\\\x=\frac{57}{18}$

Simplify

$x=\frac{19}{6}$

<em>Find the length of DC</em>

$DC=AC-2x$

substitute the given values

$DC=9-2(\frac{19}{6})$

$DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units$

8 0

3 years ago

I cant seem to understand this. please explain :))<br> (business math)

Alex787 [66]

Answer:

$1.50 bro

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers