For this sort of problem, you need to be familiar with prefixes.
So:
megabyte = 
bytes
kilobyte = 
bytes
and a regular byte would just be 
Now, you will need to do a conversion:
I'm going to explain this just in case, but we convert megabytes to regular bytes in the first half by using the information I gave you above. (In one megabyte, there are 
bytes!)
In the second fraction thought, remember one kilobyte is bytes. However, you usually only see one of each thing on the bottom of fractions, so you need to add a negative sign to the 3. (technically you could just do 
, but I think it is more correct to do write it out how I did).
*** They do equal the same thing though! Do whichever way is easier for you!
Now, your answer should be:
kilobytes (1000 kilobytes)
Hope this helped!
Answer:
n = -7,6
Step-by-step explanation:
n(n+1)+3=45
distributive property: a(b+c) = ab+ac
n²+n+3 = 45
n²+n -42 = 0
factor now
(n+7)(n-6) = 0
n = -7,6
Answer:
1300
Step-by-step explanation:
Let the amount put in the station's tank = x
4(400 + x) = 8100 - x Remove the brackets
1600 + 4x = 8100 - x Subtract 1600 from both sides
1600 - 1600 + 4x = 8100 - 1600 - x Do the subtraction
4x = 6500 - x Add x to both sides
4x + x = 6500 - x + x
5x = 6500 Divide by 5
5x/5 = 6500/5
x = 1300
1300 gallons were added to the station's tank.
domain is {2.4, 4.8, 6.3, 8.8, 10.1 }
For domain, equate f(x) to each value in the range and solve for x
7x - 2.7 = 14.1 ⇒ x = 
= 2.4
7x - 2.7 = 30.9 ⇒ x = 
= 4.8
7x - 2.7 = 41.4 ⇒ x = 
= 6.3
7x - 2.7 = 58.9 ⇒ x = 
= 8.8
7x - 2.7 = 68 ⇒ x = 
= 10.1
Answer:
Step-by-step explanation:
he has 4.80 in dimes and quarters....dimes (d) are worth 0.10 and quarters (q) are worth 0.25
0.10d + 0.25q = 4.80
he has 6 more dimes then quarters
d = q + 6
====================
d = q + 6...so we sub q + 6 in for d, back into the other equation
0.10(q + 6) + 0.25q = 4.80
0.10q + 0.60 + 0.25q = 4.80
0.35q = 4.80 - 0.60
0.35q = 4.20
q = 4.20 / 0.35
q = 12 <====== there is 12 quarters
d = q + 6
d = 12 + 6
d = 18 <===== there is 18 dimes
