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pshichka [43]
3 years ago
7

on 20 of 22 Which equation describes the line with slope 8 that contains the point (-3, -6)? O A. y + 3 = 8(x+6) O B. y-3 = 8(x-

6) c. y - 6 = 8(x-3) O D. y + 6 = 8(x + 3)¹​
Mathematics
2 answers:
Rus_ich [418]3 years ago
4 0

Answer:

Hi, I just wanted to say that I got this question a few days ago on my test!

I haven't gotten my grade yet and I dont know if I got it right but I hope you figure it out! Best of luck to you!

son4ous [18]3 years ago
3 0

The equation of a line in point slope form is :

Y - y1 = m(x -x1)

M is the slope given as 8

Y1 and x1 are the x and y values of the given point:

Y - (-6) = 8(x - (-3))

Rewrite as:

Y + 6 = 8(x + 3)

The answer is D

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The ball's height (in meters above the ground), xxx seconds after Antoine threw it, is modeled by: h(x)=-2x^2+4x+16 How many sec
zlopas [31]

Answer:

Step-by-step explanation:

If we are given the quadratic model, we know that the height of anything on the ground is 0 meters, so that model becomes

0=-2t^2+4t+16 I changed your x's to t's since t is for time.

Now we need to factor that quadratic and solve for time:

0=-2(t^2-2t-8)

Since -2 definitely does not equal 0, then

t^2-2t-8=0

Factor that and find t values of 4 and -2.  Again, we know that time will never be negative, so

t = 4 seconds.

5 0
3 years ago
Read 2 more answers
How do you do this. Please give a full answer and explain why.
OverLord2011 [107]

<u>L</u><u>a</u><u>w</u><u> </u><u>o</u><u>f</u><u> </u><u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u>

\displaystyle \large{ {a}^{ - n}  =  \frac{1}{ {a}^{n} } }

Compare the terms.

\displaystyle \large{ {a}^{ - n}  =   {( - 2)}^{ - 3} }

Therefore, a = -2 and n = 3. From the law of exponent above, we receive:

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{ {( - 2)}^{ 3} } }

<u>E</u><u>x</u><u>p</u><u>o</u><u>n</u><u>e</u><u>n</u><u>t</u><u> </u><u>D</u><u>e</u><u>f</u><u>.</u> (For cubic)

\displaystyle \large{ {a}^{3}  = a \times a \times a }

Factor (-2)^3 out.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{( - 2) \times ( - 2) \times ( - 2)}}

(-2) • (-2) = 4 | Negative × Negative = Positive.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{4 \times ( - 2)}}

4 • (-2) = -8 | Negative Multiply Positive = Negative.

\displaystyle \large{ {( - 2)}^{ - 3}  =  \frac{1}{  - 8}}

If either denominator or numerator is in negative, it is the best to write in the middle or between numerator and denominators.

Hence,

\displaystyle \large \boxed{ {( - 2)}^{ - 3}  =  -  \frac{1}{  8}}

The answer is - 1 / 8

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3 years ago
What is the range of the exponential function f(x)=2•7x
sergeinik [125]

f(x) cannot be 0 or less than zero, but can approach+ infinity

Answer is (0, ∞)

5 0
3 years ago
1 What is the RANGE for the following graph?<br><br> PLEASE HELP 25 POINTS
xenn [34]
I cant see the picture
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3 years ago
Hi can you guys help me know how to explain this?
ludmilkaskok [199]
10 x 25 = 250, well 20 x 25 is just double that, its 10 doubled x 25 so he probably just added it up. repeated addition really helps with times tables. 
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