Hi!
<h3>
Your answer is the first option, 0.17.</h3>
To solve this, we will have to do a few things.
- Solve for the area of the triangle
- Solve for the area of the rectangle
- Find what percent the area of the triangle is of the area of the rectangle
<h3><u>
STEP ONE</u></h3>
<u>Area of a triangle:</u> 
Use the given values to plug it into the formula:
The area of the triangle is 12 centimeters squared.
<h3><u>
STEP TWO</u></h3>
<u>Area of a rectangle:</u> 
Use the given values to plug it into the formula:
The area of the rectangle is 70 centimeters squared.
<h3><u>
STEP THREE</u></h3><h3 />
To do this step, we must divide the area of the triangle by the area of the rectangle.
This will give us the percent that the triangle is of the rectangle, and hence will give us the probability of it landing inside of the rectangle.
So:
<em>Therefore, the probability that a point chosen randomly inside the rectangle is in the triangle is 0.17.</em>
The graph is misleading because the year’s interval is not constant.
The first year to the second year, the gap is 1 year; in the second to the
third year, the gap is 2; in the third to the fourth year is 4; and the fourth
to the fifth year is 6.
X has to be less than 2 which means the only answer is 1
The coordinates of the corners in the scale drawing of the desing are:
H = (2,0)
I = (0,0)
J = (0,4)
K = (2,4)
That makes the lengths of the segments be:
HI = 2 - 0 = 2
JK = 2 - 0 =2
JI = 4 - 0 = 4
KH = 4 - 0 = 4
Now check the segments of the actual cover:
H'I' = 10 - 0 = 10
K'J' = 10 - 0 = 10
J'I' = 16 - 0 = 16
K'H' = 16 - 0 = 16
Now check corresponding segments meet proportionality criterium, which is needed for similarity:
H'I' / HI = 10 /2 = 5
K'J' / KJ = 10 / 2 = 5.
So far we this is fine.
JI / J'I' = 16 / 4 = 4............ then not, the ratio is not the same ratio of the other two segments, which implies that the scale used for the vertical segments is different to the scale used for the horizontal segments, driving to a non similar figure.
Answer: no, because the corresponding sides are not proportional
D) 6 x 3+y 2
hope this helps
