Answer:
21 + 3a
Step-by-step explanation:
3 (7+a)
distribute 3 into parentheses:
21 + 3a
<span> here
7 7/8
= [ (8*7) + 7 ] / 8
= (56 + 7) / 8
=63 / 8
similarly,
3 1/4
=[ (4*3) + 1] / 4
= (12 + 1) / 4
= 13/4
----------------------------
now put the values
7 7/8 - 3 1/4
= 63/8 - 13/4
here, take LCM of 8 & 4 which is 8.
now,
[ (1*63) - (2 * 13) ] / 8
= (63 - 26) / 8
= 37/8
= 4 5/8........................[ here, divide 37 by 8 which gives reminder as 5 and divisible value as 4 ]</span>
<h2><em>= 2(x-3) + 2(7x+1) </em></h2><h2><em>since there are 4 sides, 2 which have the same dimensions
</em></h2><h2><em>
</em></h2><h2><em>= 2x - 6 + 14x + 1 </em></h2><h2><em>= 16x - 5</em></h2><h2><em /></h2><h2><em>HOPE IT HELPS (◕‿◕✿) </em></h2><h2><em>SMILE!!
</em></h2><h2><em /></h2>
We know that 12 equals one dozen. It is not asking for a dozen, but for 9 dozen. So, we need to multiply 9 by 12. 9*12 = 108.
It says the rolls of first aid tape were divided equally into 4 boxes. We need to divide these 108 rolls into 4 equal groups, since that is what took place in the problem. So, we divide 108 by 4.
108/4 = 27. There are 27 rolls in each box.
<h3>
Answer: C) -1/2</h3>
=============================================
Explanation:
We'll apply the derivative to get
g(x) = 4x^3 + 3x^2
g ' (x) = 3*4x^2 + 2*3x
g ' (x) = 12x^2 + 6x
Set that equal to 0 and solve for x. We do this to find where the horizontal tangents are located.
g ' (x) = 0
12x^2 + 6x = 0
6x(2x + 1) = 0
6x = 0 or 2x+1 = 0
x = 0 or x = -1/2
Adding those two said solutions yields us the final answer choice C
