All categories

3 years ago

I need help!!! and make sure its 100 percent right!! my graduation is at rate of not passing

Mathematics

2 answers:

geniusboy [140]3 years ago

6 0

Answer:

I'm not 100% sure I'm right but I think x = -1

because it says "f(x)" and then it says"Find f(-1)" so that is why I think x = -1

balu736 [363]3 years ago

6 0

Answer:

I'm not sure I have no clue

You might be interested in

he graph of y=e^tan x-2 crosses the x axis at one point in the interval [0,1]. What is the slope of the graph at this point?

notsponge [240]

You need to differentiate the equation to find the answer

4 0

3 years ago

If someone runs 4 miles in 30 minutes how many will they run in 48 minutes

kakasveta [241]

First find out how fast they run 1 mile by dividing the time they ram ( 30 minutes) by the number of miles they ran (4)

30 minutes / 4 miles = 7.5 minutes per mile

now we know how fast they run divide the new overall time (48 minutes) by the speed (7.5 minutes) to find the number of miles they will run

48 / 7.5 = 6.4 miles

4 0

3 years ago

How many triangles and quadrilaterals altogether can be formed using the vertices of a 7-sided regular polygon?

MAVERICK [17]

Answer: The correct option is

(E) 70.

Step-by-step explanation: We are given to find the number of triangles and quadrilaterals altogether that can be formed using the vertices of a 7-sided regular polygon.

To form a triangle, we need any 3 vertices of the 7-sided regular polygon. So, the number of triangles that can be formed is

$n_t=^7C_3=\dfrac{7!}{3!(7-3)!}=\dfrac{7\times6\times5\times4!}{3\times2\times1\times4!}=35.$

Also, to form a quadrilateral, we need any 4 vertices of the 7-sided regular polygon. So, the number of quadrilateral that can be formed is

$n_q=^7C_4=\dfrac{7!}{4!(7-4)!}=\dfrac{7\times6\times5\times4!}{4!\times3\times2\times1}=35.$

Therefore, the total number of triangles and quadrilaterals is

$n=n_t+n_q=35+35=70.$

Thus, option (E) is CORRECT.

8 0

3 years ago

Can someone please help me out with 15 and 16

vredina [299]

Answer:

Step-by-step explanation:

6 0

3 years ago

The desired percentage of SiO2 in a certain type of aluminous cement is 5.5. To test whether the true average percentage is 5.5

miskamm [114]

Answer:

z=-3.25

$p_v =2*P(z$

Step-by-step explanation:

1) Data given and notation

$\bar X=5.24$ represent the mean production for the sample

$\sigma=0.32$ represent the sample standard deviation for the sample

$n=16$ sample size

$\mu_o =5.5$ represent the value that we want to test

$\alph=0.05a$ represent the significance level for the hypothesis test.

z would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

Part a: State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean production is different from 5.5 tons, the system of hypothesis would be:

Null hypothesis: $\mu =5.5$

Alternative hypothesis: $\mu \neq 5.5$

If we analyze the info given we know the population deviation so is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:

$z=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$z=\frac{5.24-5.5}{\frac{0.32}{\sqrt{16}}}=-3.25$

P-value

Since this is a two side test the p value would be:

$p_v =2*P(z$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, so we can conclude that the production its significant different compared to the desired percentage of SiO2 of 5.5 at 5% of signficance.

7 0

3 years ago