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Tomtit [17]
3 years ago
11

Find the approximate location of 2/3, 1/2, and 3/8 on a number line 0 to 1

Mathematics
2 answers:
schepotkina [342]3 years ago
5 0

Answer:

0.6 (terminating), 0.5, 0.375

Step-by-step explanation:

I would assume you are wanting these in decimal form. In that case, you would have:

2/3 = 0.6 (terminating)

1/2 =  0.5

3/8 = 0.375

Sphinxa [80]3 years ago
5 0
Well you know that 1/2 will be in the middle of 0 and 1 so you can place that point, then 2/3 is just a little bigger than that so you can divide your whole number line (of 0 to 1 ) into three sections and place 2/3 on the second line, then, 3/8 is almost 4/8=1/2 so just put it a little below your 1/2 point
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luda_lava [24]
Hope this helps you.

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3 years ago
Find the integration of (1-cos2x)/(1+cos2x)
slega [8]

Given:

The expression is:

\dfrac{1-\cos 2x}{1+\cos 2x}

To find:

The integration of the given expression.

Solution:

We need to find the integration of \dfrac{1-\cos 2x}{1+\cos 2x}.

Let us consider,

I=\int \dfrac{1-\cos 2x}{1+\cos 2x}dx

I=\int \dfrac{2\sin^2x}{2\cos^2x}dx         [\because 1+\cos 2x=2\cos^2x,1-\cos 2x=2\sin^2x]

I=\int \dfrac{\sin^2x}{\cos^2x}dx

I=\int \tan^2xdx                      \left[\because \tan \theta =\dfrac{\sin \theta}{\cos \theta}\right]

It can be written as:

I=\int (\sec^2x-1)dx             [\because 1+\tan^2 \theta =\sec^2 \theta]

I=\int \sec^2xdx-\int 1dx

I=\tan x-x+C

Therefore, the integration of \dfrac{1-\cos 2x}{1+\cos 2x} is I=\tan x-x+C.

8 0
3 years ago
Aisha is a sales clerk at Macy's. She paid $8.00 per hour plus a commission of 4% on all sales. Assuming Aisha works 39 hours an
steposvetlana [31]

Answer:

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Step-by-step explanation:

If Aishat is paid $8.00 per hour, then for 39 hours, she will get

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4000 × 4/100

= $160

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6 0
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Oksanka [162]
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8 0
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BaLLatris [955]

Answer:

y = -(5/2)x -2

Explanation:

The general formula for a straight line is y – mx + b.

The image below shows the graph of the line.

Step 1. <em>Calculate the slope</em>.

Slope = m = Δy/Δx = (y₂-y₁)/(x₂-x₁)

x₁ = 0; y₁ = -2

x₂ = -2; y₂ = 3     Calculate m

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m = -5/2

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Step 3. <em>Write the equation </em>for the graph

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3 0
3 years ago
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