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LUCKY_DIMON [66]
4 years ago
10

A vessel (see the figure) comprises of into two chambers

Physics
1 answer:
r-ruslan [8.4K]4 years ago
4 0

Answer:

(C) 2P

Explanation:

Ideal gas law states:

PV = nRT

n (the number of moles) and R (ideal gas constant) are constant, so we can say:

(PV / T) before = (PV / T) after

Chamber X starts at pressure P, volume V, and temperature T.  At equilibrium, the pressure is Px, the volume is Vx, and temperature 3T.

PV / T = Px Vx / 3T

Chamber Y starts at pressure P, volume V, and temperature T.  At equilibrium, the pressure is Py, the volume is Vy, and temperature T.

PV / T = Py Vy / T

Substituting and simplifying:

Px Vx / 3T = Py Vy / T

Px Vx / 3 = Py Vy

Since the chambers are at equilibrium, Px = Py:

Vx / 3 = Vy

Vx = 3 Vy

The total volume is the same as before, so:

Vx + Vy = 2V

Substituting:

(3 Vy) + Vy = 2V

4 Vy = 2V

Vy = V / 2

Now if we substitute into our equation for chamber Y:

PV / T = Py (V/2) / T

PV = Py (V/2)

Py = 2P

The pressure in chamber Y (and chamber X) doubles at equilibrium.

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