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3 years ago

7

Explain why smoke particles in air move about faster if the temp of the air is increased??

1 answer:

Harlamova29_29 [7]3 years ago

6 0

Answer:

kinetic energy increases with the energy which causes the particles to move faster resulting in increases collision rates and rate of diffusion.

Explanation:

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A student blows up a balloon and then places it in a very cold freezer. After a few hours, the balloon has shrunk. Which of the

Harman [31]

<span>The reason why the balloon shrunk is because as the balloon gets cooler, the molecules lose energy and move closer together causing the balloon to shrink.</span>

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3 years ago

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What is dark energy?

Gnesinka [82]

Dark energy is what is causing the accelerating expansion of the universe. It can also be defined as the theoretical energy that counteracts or acts against gravity. Others also define it as a theoretical, new kind of dynamic energy field that fills space, but whose energy has an effect opposite to that of normal energy.

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3 years ago

A high-speed railway car goes around a flat, horizontal circle of radius 480 m at a constant speed. The magnitudes of the horizo

kvv77 [185]

Answer:

Net force ( F ) = 208 N.

Speed of car ( v ) = 68.58 m/s.

Explanation:-

The radius ( r ) = 480 m.

Mass of passenger ( m ) = 65 kg.

Horizontal force ( $f_{x}$ ) = 208 N.

Vertical force ( $f_{n}$ ) = 637 N.

Net vertical component of force ( $f_{x}$ ) = m*g - 637 = 65 * 9.8 - 637 = 0 N.

a ) magnitude of net force .

$F = \sqrt{f^{2} _{x} + f^{2} _{y} } = \sqrt{208^{2} + 0^{2} }$ = 208 N.

b) The speed of car.

$f_{n} = \frac{m*v^{2} }{r}$ where v is the velocity.

$637 = \frac{65 *v^{2} }{480}$

v² = 4704

v = 68.58 m/s.

6 0

3 years ago

How much heat is absorbed from a 56.00 g sample of Mercury when its tempreature change is 289K?

AveGali [126]

Heat required to raise the temperature of mercury is given as

$Q = ms\Delta T$

here given that

m = 56 g

s = specific heat capacity of mercury = 0.140 J/g C

$\Deta T = 289 k$

now here we have

$Q = 56 * 0.140 * 289$

$Q = 2265.76 J$

so it required 2265.76 J of heat

8 0

3 years ago

Hey scooters dragging of 520 kg walk-through forest at a constant speed of 3.5 m/s. If the scooter is applying a force of 1850 N

Simora [160]

The coefficient of friction is 0.363

Explanation:

There are two forces acting on the scooter in the horizontal direction:

- The applied force, F = 1850 N, forward

- The frictional force, $F_f$ , backward

Since the scooter is moving at constant speed, the acceleration is zero, so the net force acting on the scooter must be zero. Therefore we can write:

$F-F_f = 0\\F_f = F = 1850 N$

The frictional force can be written as

$F_f = \mu R$ (1)

where

$\mu$ is the coefficient of friction

R is the normal reaction of the ground on the scooter

For a flat horizontal surface, there is equilibrium along the vertical direction, so the normal reaction is equal to the weight:

$R = W = mg$

where

m = 520 kg is the mass

$g=9.8 m/s^2$ is the acceleration of gravity

Substituting into (1),

$F_f = \mu mg = 1850 N$

and solving for $\mu$ ,

$\mu=\frac{F_f}{mg}=\frac{1850}{(520)(9.8)}=0.363$

Learn more about friction:

brainly.com/question/6217246

brainly.com/question/5884009

brainly.com/question/3017271

brainly.com/question/2235246

#LearnwithBrainly

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4 years ago