A continental air mass originates from lmd
Answer:
<em>The Strength of the electric field produced = 2 × 10⁷ N/C</em>
Explanation:
<em>Electric Field:</em> This is defined as the region where an electric force is experienced.
<em>Electric Field Strength: </em><em>The intensity of an electric field at any point is defined as the force per unit charge which it exert at that point. It direction is that of the force exerted on a positive charge.</em>
<em>It is represented mathematically as,</em>
<em>E = F/Q ................................. Equation 1</em>
<em>Where E = Electric field strength, F = electric force, Q = test charge.</em>
<em>Given: F = 3.2 × 10⁻⁴ N, Q = 1.6 × 10⁻¹¹ C</em>
<em>Substituting these values into equation 1</em>
<em>E= 3.2 × 10⁻⁴/1.6 × 10⁻¹¹ </em>
<em>E= 2 × 10⁷ N/C</em>
<em>Thus the Strength of the electric field produced = 2 × 10⁷ N/C</em>
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Answer:
N=mg
g=10-3=7
n=40×7
n=280
Explanation:
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Answer:
C) The spring constant of each half will be twice the spring constant of the original long spring since it will stretch only half as much under the same tension.
Explanation:
Hooke's law states that the force needed to extend or compress a spring by a distance is proportional to that distance. If is given as:
F = ke, where F is the force applied, k is spring constant and e is the extension.
If a force f is applied to a spring with a spring constant k and by a distance stretched (x) then:
k = F / x
For half the spring, if the same force F is applied, the stretch would be half (x/2), hence the spring constant C is:
C = F / (x/2)
C = 2 (F / x) = 2 * spring constant of original spring