Answer:
 w = √[g /L (½ r²/L2 + 2/3 ) ]
When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE
Explanation:
We can simulate this system as a physical pendulum, which is a pendulum with a distributed mass, in this case the angular velocity is
           w² = mg d / I
In this case, the distance d to the pivot point of half the length (L) of the cylinder, which we consider long and narrow
          d = L / 2
The moment of inertia of a cylinder with respect to an axis at the end we can use the parallel axes theorem, it is approximately equal to that of a long bar plus the moment of inertia of the center of mass of the cylinder, this is tabulated
         I = ¼ m r2 + ⅓ m L2
         I = m (¼ r2 + ⅓ L2)
now let's use the concept of density to calculate the mass of the system
         ρ = m / V
         m = ρ V
the volume of a cylinder is
          V = π r² L
           m =  ρ π r² L
let's substitute
         w² = m g (L / 2) / m (¼ r² + ⅓ L²)
         w² = g L / (½ r² + 2/3 L²)
         L >> r
          w = √[g /L (½ r²/L2 + 2/3 ) ]
When the mass of the cylinder changes if its external dimensions do not change the angular velocity DOES NOT CHANGE
 
        
             
        
        
        
The movement of air flows from high pressure to low pressure
        
             
        
        
        
Answer with Explanation:
We are given that 
Constant speed of Jane=12.6 m/s
a.When Fred can throw the ball 30  m/s
We have to find the angle relative to the horizontal when he throw the ball in order for Sue to see the ball travel vertically upward.
Let  be the angle .
 be the angle .
Therefore, 



b.We have to find the height to which ball reach.



 
        
             
        
        
        
Answer:
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Answer:
Given,
   mass of man = 100 N = 10 kg
    height = h = 25m
    since the man does not move anything with his force, work done by him is zero
    work done on the man = gain in potential energy
    P.E=mgh
    P.E=10×9.8×25
   P.E=2.45KJ
Explanation:
so, potential energy gained by man is 2.45 KJ