I used Excel to create the tables and the graphs.
I attached both the tables and the graphs.
You should replace the numbers of the x-axis (in both graphs) by the numbers as a fraction of pi. Those numbers are also included in the table, so you should not have problems with that.
Open and see tha file attached with the answer to your question..
Hi,
That would be a circle because it has 360 degrees.
Answer:12
Step-by-step explanation:
A vertical asymptote occurs when function limit goes to infinity.
cot is reciprocal of tangent.
cot = 1/tan, Find where tan = 0, since 1/0 goes to infinity.
tan(a) = 0 when a = 0,pi
Now Apply coefficient inside cot function.
x/2 = 0,pi
x = 0, 2pi
Therefore, vertical asymptotes occur when x = 0 or 2pi
If you're asking for the final term, the solution is to take b(from ax^2+bx+c), half it, and then square it. So in this case, b is 8.
8/2=4
4^2=16
So:
v^2+8v+16
If you factor it, it becomes (v+4)^2, which shows that its a perfect square.
