Answer:
if it's area the area would be the length of the diameter of the semi circle which is the height of the triangle multiplied by the base of the triangle to find the area of the triangle then to find the area of the circle would be pie multiplied by the diameter divided by two squared
then the total area would be the area of the triangle plus the area of the half circle
Answer: Its B
Step-by-step explanation: Hope this was helpful I am not to sure this is the right answer but let me know if it is
GF = GH
<F = <H
<E=<G
or
<EGF = <HGJ
answer
<span>e) AAS
</span><span>d) ASA</span>
Answer:
g²/f⁷h
Step-by-step explanation:
Because f⁹-f²=f⁷ which leaves f⁷ on the bottom, g³-g=g² which leaves g² on the top, and h⁵-h⁴=h which leaves h on the bottom.
Theory:
The standard form of set-builder notation is <span>
{ x | “x satisfies a condition” } </span>
This set-builder notation can be read as “the set
of all x such that x (satisfies the condition)”.
For example, { x | x > 0 } is
equivalent to “the set of all x such that x is greater than 0”.
Solution:
In the problem, there are 2 conditions that must
be satisfied:
<span>1st: x must be a real number</span>
In the notation, this is written as “x ε R”.
Where ε means that x is “a member of” and R means “Real number”
<span>2nd: x is greater than or equal to 1</span>
This is written as “x ≥ 1”
Answer:
Combining the 2 conditions into the set-builder
notation:
<span>
X =
{ x | x ε R and x ≥ 1 } </span>
