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BabaBlast [244]
3 years ago
8

Xavier needs to create 100 grams of a drink mix containing 18% citric acid, 8% flavoring, and 74% sugar. How much of mixture C s

hould he use?
A) 0 grams
B) 20 grams
C) 40 grams
D) 60 grams

Mathematics
1 answer:
Sedbober [7]3 years ago
4 0

Answer:

The answer is 60

Step-by-step explanation:

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At the fast food restaurant, an order of fries costs $1.13 and a drink costs $0.95. How much would it cost to get 3 orders of fr
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Step-by-step explanation:

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HELP PLEASE IM IN A TIMED TESTTTT !!!
mixas84 [53]

Answer:

Step-by-step explanation:

2. 9a +4c=43

a+c=7

The total tickets for adults and children = 7 (a+c =7)       7 people in all

price for adult = $9  (9a)   Price per child =$4 (4c)

total price =$ 43

  9a +7c = 43

3 0
3 years ago
Percentage grade averages were taken across all disciplines at a particular university, and the mean average was found to be 83.
Georgia [21]
Correct Ans:
Option A. 0.0100

Solution:
We are to find the probability that the class average for 10 selected classes is greater than 90. This involves the utilization of standard normal distribution.

First step will be to convert the given score into z score for given mean, standard deviation and sample size and then use that z score to find the said probability. So converting the value to z score:

z-score= \frac{90-83.6}{ \frac{8.7}{ \sqrt{10} } } \\  \\ 
z-score =2.326

So, 90 converted to  z score for given data is 2.326. Now using the z-table we are to find the probability of z score to be greater than 2.326. The probability comes out to be 0.01.

Therefore, there is a 0.01 probability of the class average to be greater than 90 for the 10 classes.
5 0
4 years ago
Select all the equations where b= 11 is a solution.<br> Choose 2 answers:
Allushta [10]

Answer:

what do you mean there is no pictures

5 0
3 years ago
Consider a sample with data values of 27, 24, 21, 16, 30, 33, 28, and 24. Compute the 20th, 25th, 65th, and 75th percentiles. 20
densk [106]

Answer:

P_{20} = 20 --- 20th percentile

P_{25} = 21.75  --- 25th percentile

P_{65} = 27.85   --- 65th percentile

P_{75} = 29.5   --- 75th percentile

Step-by-step explanation:

Given

27, 24, 21, 16, 30, 33, 28, and 24.

N = 8

First, arrange the data in ascending order:

Arranged data: 16, 21, 24, 24, 27, 28, 30, 33

Solving (a): The 20th percentile

This is calculated as:

P_{20} = 20 * \frac{N +1}{100}

P_{20} = 20 * \frac{8 +1}{100}

P_{20} = 20 * \frac{9}{100}

P_{20} = \frac{20 * 9}{100}

P_{20} = \frac{180}{100}

P_{20} = 1.8th\ item

This is then calculated as:

P_{20} = 1st\ Item +0.8(2nd\ Item - 1st\ Item)

P_{20} = 16 + 0.8*(21 - 16)

P_{20} = 16 + 0.8*5

P_{20} = 16 + 4

P_{20} = 20

Solving (b): The 25th percentile

This is calculated as:

P_{25} = 25 * \frac{N +1}{100}

P_{25} = 25 * \frac{8 +1}{100}

P_{25} = 25 * \frac{9}{100}

P_{25} = \frac{25 * 9}{100}

P_{25} = \frac{225}{100}

P_{25} = 2.25\ th

This is then calculated as:

P_{25} = 2nd\ item + 0.25(3rd\ item-2nd\ item)

P_{25} = 21 + 0.25(24-21)

P_{25} = 21 + 0.25(3)

P_{25} = 21 + 0.75

P_{25} = 21.75

Solving (c): The 65th percentile

This is calculated as:

P_{65} = 65 * \frac{N +1}{100}

P_{65} = 65 * \frac{8 +1}{100}

P_{65} = 65 * \frac{9}{100}

P_{65} = \frac{65 * 9}{100}

P_{65} = \frac{585}{100}

P_{65} = 5.85\th

This is then calculated as:

P_{65} = 5th + 0.85(6th - 5th)

P_{65} = 27 + 0.85(28 - 27)

P_{65} = 27 + 0.85(1)

P_{65} = 27 + 0.85

P_{65} = 27.85

Solving (d): The 75th percentile

This is calculated as:

P_{75} = 75 * \frac{N +1}{100}

P_{75} = 75 * \frac{8 +1}{100}

P_{75} = 75 * \frac{9}{100}

P_{75} = \frac{75 * 9}{100}

P_{75} = \frac{675}{100}

P_{75} = 6.75th

This is then calculated as:

P_{75} = 6th + 0.75(7th - 6th)

P_{75} = 28 + 0.75(30- 28)

P_{75} = 28 + 0.75(2)

P_{75} = 28 + 1.5

P_{75} = 29.5

7 0
3 years ago
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