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mr Goodwill [35]
3 years ago
8

A tire manufacturer estimates that their tires last, an average of 40,000 miles, with a standard deviation of 5000. What is the

probability that a randomly chosen tire from this manufacturer lasts between 30,000 miles and 50,000 miles? (Give your answer as a decimal rounded to 4 decimal places.) check Reference Answer: 2. The daily high temperature on October 31 in a certain city is normally distributed with 50 and 0 8. What is the probability that the high temperature on October 31 in a randomly chosen year will be between 46 degrees and 58 degrees? (Give your answer as a decimal rounded to 4 decimal places.)
Mathematics
1 answer:
Oxana [17]3 years ago
3 0

Answer:

0.9554,0.8188

Step-by-step explanation:

Given that a tire manufacturer estimates that their tires last, an average of 40,000 miles, with a standard deviation of 5000.

X - duration of tires is N(40000,5000)

Or Z = \frac{x-40000}{5000} is N(0,1)

the probability that a randomly chosen tire from this manufacturer lasts between 30,000 miles and 50,000 miles

=P(30000

------------------------------------

2) Given that the daily high temperature on October 31 in a certain city is normally distributed with 50 and 8

Y - daily high temp on Oct 31 is N(50,8)

Or Z = \frac{x-50}{8} is N(0,1)

the probability that a randomly chosen tire from this manufacturer lasts between 46 degrees and 58 degrees

=P(46

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24 swimmers are swimming in the pool. 9 of them are female. What fraction of swimmers are male?
Korolek [52]

Answer:

15/24 or 5/8

Step-by-step explanation:

Well 9 are female

The rest of the 24 has to be male so

24-9=15

15/24 or 5/8

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3 years ago
SOLVE THE QUESTION BELOW ASAP
qwelly [4]

Answer:

Part A) The graph in the attached figure (see the explanation)

Part B) 16 feet

Part C) see the explanation

Step-by-step explanation:

Part A) Graph the function

Let

h(t) ----> the height in feet of the ball above the ground

t -----> the time in seconds

we have    

h(t)=-16t^{2}+98

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex is a maximum

To graph the parabola, find the vertex, the intercepts,  and the axis of symmetry

<em>Find the vertex</em>

The function is written in vertex form

so

The vertex is the point (0,98)

Find the y-intercept

The y-intercept is the value of the function when the value of t is equal to zero

For t=0

h(t)=-16(0)^{2}+98

h(0)=98

The y-intercept is the point (0,98)

Find the t-intercepts

The t-intercepts are the values of t when the value of the function is equal to zero

For h(t)=0

-16t^{2}+98=0

t^{2}=\frac{98}{16}

square root both sides

t=\pm\frac{\sqrt{98}}{4}

t=\pm7\frac{\sqrt{2}}{4}

therefore

The t-intercepts are

(-7\frac{\sqrt{2}}{4},0), (7\frac{\sqrt{2}}{4},0)

(-2.475,0), (2.475,0)

Find the axis of symmetry

The equation of the axis of symmetry in a vertical parabola is equal to the x-coordinate of the vertex

so

x=0 ----> the y-axis

To graph the parabola, plot the given points and connect them

we have

The vertex is the point (0,98)

The y-intercept is the point (0,98)

The t-intercepts are (-2.475,0), (2.475,0)

The axis of symmetry is the y-axis

The graph in the attached figure

Part B) How far is the artifact fallen from the time t=0 to time t=1

we know that

For t=0

h(t)=-16(0)^{2}+98

h(0)=98\ ft

For t=1

h(t)=-16(1)^{2}+98

h(1)=82\ ft

Find the difference

98\ ft-82\ ft=16\ ft

Part C) Does the artifact fall the same distance from time t=1 to time t=2 as it does from the time t=0 to time t=1?

we know that

For t=1

h(t)=-16(1)^{2}+98

h(1)=82\ ft

For t=2

h(t)=-16(2)^{2}+98

h(2)=34\ ft

Find the difference

82\ ft-34\ ft=48\ ft

so

The artifact fall 48 feet from time t=1 to time t=2 and fall 16 feet from time t=0 to time t=1

therefore

The distance traveled from t=1 to t=2 is greater than the distance traveled from  t=0 to t=1

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We also need to check coming from the right. We will use the number .00001 for x
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<span>\lim_{x\to 0} \frac{csc(3x)}{cot(x)} = \frac{1}{3}</span>

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