3 years ago

Need help on the mean and the median 1-10 pleaaaase for brainlest answer and thanks !!!!!!!!!!

Mathematics

1 answer:

kati45 [8]3 years ago

8 0

For number one the media is 22 and 5

You might be interested in

If each quadrilateral below is a square, find the missing measures<br><br>solve for X

Studentka2010 [4]

Answer:

i think x = 18.5

Step-by-step explanation:

6x-21 = 90°

6x = 90+21

6x = 111

x = 111/6

x = 18.5

3 0

2 years ago

3x^2+7x=30______________

goblinko [34]

Answer:

if you need help with problems like that I suggest algebra calculator or math away

8 0

3 years ago

Read 2 more answers

Subract (8x+6)-(x+4)

NeX [460]

Step-by-step explanation:

8x + 6) - (x + 4)

8x + 6 - (x + 4)

8x + 6 - x - 4

7x + 2

4 0

3 years ago

Compare 8 ⋅ 107 to 2 ⋅ 104

miss Akunina [59]

8 x 107 = 856
2 x 104 = 208
856 - 208 = 648

3 0

3 years ago

Consider this equation. cos(theta) = (-2√5)/5. If theta is an angle in quadrant II, what is the value of sin(theta)? NO LINKS!!!

vlada-n [284]

In second quadrant sin and cosec are positive

$\\ \tt\hookrightarrow sin^2\theta=1-cos^2\theta$

$\\ \tt\hookrightarrow sin^2\theta=1-(\dfrac{-2\sqrt{5}}{5})^2$

$\\ \tt\hookrightarrow sin^2\theta=1-\dfrac{20}{25}$

$\\ \tt\hookrightarrow sin^2\theta=\dfrac{5}{25}$

$\\ \tt\hookrightarrow sin\theta=\dfrac{\sqrt{5}}{5}$

$\\ \tt\hookrightarrow sin\theta=\dfrac{1}{\sqrt{5}}$

5 0

2 years ago