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3 years ago

Which angle forms a vertical pair with nsm a.osl b.smn c.snm d.osn

Mathematics

2 answers:

malfutka [58]3 years ago

6 0

Answer: Option 'a' is correct.

Step-by-step explanation:

Since we have given that ∠NSM,

we need to find is vertical angles of ∠NSM,

1) ∠OSL is a vertical angle of ∠NSM as it has one common vertex and all other are collinear points.

2) ∠SMN can't be vertical angle as vertical angles must be equal at common vertex but it does not do that it forms angle on M rather than on S.

3) ∠SNM can't be vertical angles as vertical angles must be equal at common vertex but it does not do that it forms angle on N rather than on S.

4) ∠OSN can't be vertical angle as vertical angles must have only one common vertex but in this case it has two common vertex i.e. S and N. so it will be linear pair.

Hence, Option 'a' is correct.

ICE Princess25 [194]3 years ago

4 0

Your answer is snm or c

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3 years ago

Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm

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Answer:

$y=2x^2-4x-8$

Step-by-step explanation:

<u>Factored form of a parabola</u>

$y=a(x-p)(x-q)$

where:

p and q are the x-intercepts.
a is some constant.

Given x-intercepts:

(1+√5, 0)
(1-√5, 0)

Therefore:

$\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))$

$\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})$

To find a, substitute the given point (4, 8) into the equation and solve for a:

$\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8$

$\implies a(3-\sqrt{5})(3+\sqrt{5})=8$

$\implies4a=8$

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Therefore, the equation of the parabola in factored form is:

$\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})$

Expand so that the equation is in standard form:

$\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)$

$\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)$

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1 year ago

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Artyom0805 [142]

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3 years ago

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Answer:

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3 years ago

Read 2 more answers

Help! Need by 10:30 to turn in and I'm confused!

Alecsey [184]

Answer:

8 boxes of tissues

5 bags of cough drops

Step-by-step explanation:

You need to write a system of equations.

x = number of tissue boxes

y = number of cough drop bags

x (number of tissue boxes) + y (number of cough drop bags) = 13 (total number of tissues and cough drops combined.

So, your first equation is

x + y = 13

Then, you need to write the second equation.

(1.69 [cost of 1 tissue box] * [number of tissue boxes]) + (1.19 [cost of one bag of cough drops] * [number of cough drop bags] = 19.47 [total cost of tissues and cough drops]

That's a lot to read, so here's the equation simplified!

1.69x + 1.19y = 19.47

Now, you have two equations:

x + y = 13

1.69x + 1.19y = 19.47

I would solve with the substitution method.

the first equation can be changed to x = 13 - y by subtracting y from both sides.

Then, your two equations are:

x = 13 - y

1.69x + 1.19y = 19.47

Now, you can plug in that value of x into the second equation!

1.69(13 - y) + 1.19y = 19.47

21.97 - 1.69y + 1.19y = 19.47

subtract 21.97 from both sides

-1.69y + 1.19y = -2.5

Add the y values

-0.5y = -2.5

divide both sides by -0.5

so, y equals 5 bags of cough drops

now that you know what y equals, plug it back into your original equation to find x!

x + y = 13

plug in y

x + 5 = 13

x = 8

so, x = 8 boxes of tissues

Hope this helps! Let me know if you have any questions!

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