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wolverine [178]
3 years ago
7

Which angle forms a vertical pair with nsm a.osl b.smn c.snm d.osn

Mathematics
2 answers:
malfutka [58]3 years ago
6 0

Answer:  Option 'a' is correct.

Step-by-step explanation:

Since we have given that  ∠NSM,

we need to find is vertical angles of ∠NSM,

1) ∠OSL is a vertical angle of ∠NSM as it has one common vertex and all other are collinear points.

2) ∠SMN can't be vertical angle as  vertical angles must be equal at common vertex but it does not do that it forms angle on M rather than on S.

3) ∠SNM can't be vertical angles as vertical angles must be equal at common vertex but it does not do that it forms angle on N rather than on S.

4) ∠OSN can't be vertical angle as vertical angles must have only one common vertex but in this case it has two common vertex i.e. S and N. so it will be linear pair.

Hence, Option 'a' is correct.

ICE Princess25 [194]3 years ago
4 0
Your answer is snm or c
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Consider the following statement. If r is any rational number and s is any irrational number, then r s is irrational. (a) Which
olganol [36]

Answer:

(a) If r is any rational number and s is any irrational number, then r/s is rational

(b) The statement is false when r is 0

Step-by-step explanation:

Given

r \to rational number

s \to irrational number

\frac{r}{s} \to irrational number

Solving (a): The negation

To get the negation of a statement, we only need to negate the end result

In other words, the number type of r and s will remain the same, but r/s will be negated.

So, the negation is:

r \to rational number

s \to irrational number

\frac{r}{s} \to rational number

Solving (b): When r/s is irrational is false

Given that:

\frac{r}{s} \to irrational number

Set r to 0

So:

\frac{r}{s} = \frac{0}{s}

\frac{r}{s} = 0 -- rational

<em>Hence, the statement is false when r is 0</em>

8 0
3 years ago
PLEASE HELP!!!!!!!! (ALGEBRA II)
qwelly [4]

Answer:

-4     4     4.5     8     20.5     32

Step-by-step explanation:

f$ \circ  $ g(x) = f(g(x))

Given,   f(x) = 2x²

and       g(x) = x - 2

Now f(g(x)) = f(x - 2) = 2(x - 2)²

We know that (a - b)² = a² - b² + 2ab

Using this we expand f(g(x)). We get:

                        f(g(x)) = 2{x² - 4x + 4}

Similarly,        g(f(x)) = g(2x²) = 2x² - 2

Now, f(g(-2))    = 2[(-2)² - 4(-2) + 4]     = 2(16)                           = 32.

Also, g(f(-2))   = 2[(-2)² - 2]                = 2(2)                             = 4.

f(g(3.5))  = 2{(3.5)² -4(3.5) + 4} = 2[12.25 - 14 + 4] = 2(2.25)    = 4.5.

g(f(3.5))  = 2{(3.5)² -2} = 2{12.25 - 2}                     = 2(10.25)   = 20.5.

f(g(0))     = 2{0 - 4(0) + 4}  = 2(4)                                               =  8.

g(f(0))     = 2{0 - 2}                         = 2(-2)                                 = -4.

Arranging them in ascending order, we get:

-4     4     4.5     8     20.5     32 would be the sequence.

5 0
3 years ago
Ok here is the question with the picture
stealth61 [152]

Answer:

The answer is <u><em>c</em></u> :D brainliest pls

3 0
3 years ago
Need help with trig!
dedylja [7]

Answer:

1. A. 4.42

2. F. 20.9

3. G. 4.57

4. A. 4.50

Step-by-step explanation:

5 0
3 years ago
Can you help me with this math problem​
Marat540 [252]

Answer:

It might be 70 because 5m has the volume of 50 m so maybe 7m in volume is 70?

3 0
3 years ago
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