Question

An investment is currently worth 1.035×108 dollars . Thirty years ago, the investment was worth ​ 2.3×105 ​ dollars. How many times greater is the value of the investment today than the value of the investment thirty years ago? A. 0.45 B.450 C.4500 D. 45,000

Answer 1

The correct option is:  B. 450

Explanation

Current value of the investment is  $1.035\times 10^8$ dollars and 30 years ago, the value of the investment was  $2.3\times 10^5$ dollars.

Suppose, the value of investment today is  $n$ times greater than the value of the investment thirty years ago.

So, the equation will be........

$n(2.3\times 10^5)=1.035\times 10^8\\ \\ n= \frac{1.035\times 10^8}{2.3\times 10^5}=0.45\times 10^3 = 450$

Thus, the value of the investment today is 450 times greater than the value of the investment thirty years ago.

Answer 2

Answer:   B. 450

Step-by-step explanation:

Given: An investment is currently worth =$1.035\times10^8$ dollars .

Thirty years ago, the investment was worth =$​2.3\times10^5$ ​dollars.

Now, the number of times the value of the investment today than the value of the investment thirty years ago is given by :-

$n=\frac{1.035\times10^8}{​2.3\times10^5}\\\\=0.45\times10^{8-5}........\text{Since }a^na^m=a^{m+n}\\\\=0.45\times10^3\\\\=0.45\times1000=450$

Hence, the value of the investment today is 450 times greater than the value of the investment thirty years ago.