Write the fraction 14/2 as a mixed number

Point WW is located at (6,4)(6,4) on the coordinate plane. Point WW is reflected over the yy-axis to create point W'W ′ . Point

yKpoI14uk [10]

Using translation concepts, the ordered pair that describes the location of W'' is: W''(-6,-4).

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction either in it’s definition or in it’s domain. Examples are shift left/right or bottom/up, vertical or horizontal stretching or compression, and reflections over the x-axis or the y-axis.

The rule for a reflection over the y-axis is:

(x,y) -> (-x,y).

Hence:

W'(-6,4).

The rule for a reflection over the x-axis is:

(x,y) -> (x, -y).

Hence:

W''(-6,-4).

More can be learned about translation concepts at brainly.com/question/4521517

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5 0

2 years ago

Please help ASAP you will get BRAINLIST.

MrRissso [65]

Answer:

Measure of LKJ is 64

Step-by-step explanation:

Here, we want to find the measure of angle LKJ

mathematically, we know that a bisector line divides an angle into 2

Since one of the divided angle is 32

The other side too will be 32

Thus, the missing value would be;

32 + 32 = 64

3 0

3 years ago

Determine the value of X

dolphi86 [110]

Answer:

The value of x is 15 ⇒ answer D

Step-by-step explanation:

* Lets talk about dilation

- A dilation is a transformation that changes the size of a figure.

- It can become larger or smaller, but the shape of the

figure does not change.

- The scale factor, measures how much larger or smaller

the image will be

- If the scale factor greater than 1, then the image will be larger

- If the scale factor between 0 and 1, then the image will be smaller

- If the scale factor is negative then the figure will reflected

* Now lets solve the problem

∵ D (o, k) (x , 9) → (-10 , -6)

- D means dilation

- o means the center of dilation is the origin

- k means the scale factor of dilation

∵ The y-coordinate of the point is 9

∵ The image has y-coordinate -6

∵ The image = The scale factor × the coordinates

∴ -6 = k × 9 ⇒ divide both sides by 9

∴ k = -6/9 = -2/3

- Lets find x by same way

∵ -10 = -2/3 × x ⇒ divide both sides by -2/3

∴ x = -10 ÷ (-2/3) ⇒ change the division to multiplication

∴ x = -10 × (-3/2) = 30/2 = 15

∴ The x-coordinate of the point before dilation is 15

* The value of x is 15

6 0

3 years ago

If 3x^2 + y^2 = 7 then evaluate d^2y/dx^2 when x = 1 and y = 2. Round your answer to 2 decimal places. Use the hyphen symbol, -,

S_A_V [24]

Taking $y=y(x)$ and differentiating both sides with respect to $x$ yields

$\dfrac{\mathrm d}{\mathrm dx}\bigg[3x^2+y^2\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[7\bigg]\implies 6x+2y\dfrac{\mathrm dy}{\mathrm dx}=0$

Solving for the first derivative, we have

$\dfrac{\mathrm dy}{\mathrm dx}=-\dfrac{3x}y$

Differentiating again gives

$\dfrac{\mathrm d}{\mathrm dx}\bigg[6x+2y\dfrac{\mathrm dy}{\mathrm dx}\bigg]=\dfrac{\mathrm d}{\mathrm dx}\bigg[0\bigg]\implies 6+2\left(\dfrac{\mathrm dy}{\mathrm dx}\right)^2+2y\dfrac{\mathrm d^2y}{\mathrm dx^2}=0$

Solving for the second derivative, we have

$\dfrac{\mathrm d^2y}{\mathrm dx^2}=-\dfrac{3+\left(\frac{\mathrm dy}{\mathrm dx}\right)^2}y=-\dfrac{3+\frac{9x^2}{y^2}}y=-\dfrac{3y^2+9x^2}{y^3}$

Now, when $x=1$ and $y=2$ , we have

$\dfrac{\mathrm d^2y}{\mathrm dx^2}\bigg|_{x=1,y=2}=-\dfrac{3\cdot2^2+9\cdot1^2}{2^3}=\dfrac{21}8\approx2.63$

3 0

3 years ago

Determine the vertical asymptote for the rational function f(x) = x - 4 over 2x - 3

k0ka [10]

Answer:

x = $\frac{3}{2}$

Step-by-step explanation:

Given

f(x) = $\frac{x-4}{2x-3}$

The denominator cannot be zero as this would make f(x) undefined.

Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non zero for this value then it is a vertical asymptote.

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = $\frac{3}{2}$

Thus x = $\frac{3}{2}$ is the vertical asymptote

5 0

3 years ago