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Alenkasestr [34]

3 years ago

12

3429111 what is the place value of the 4

1 answer:

andrew-mc [135]3 years ago

6 0

Hi friend,

3429111----

4 place value will be 40000 (4 lakh).

Hope it helps........

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What value of x satisfies the equation below?<br> 12 (x − 2) + 3x = 1/2 (x + 6) + 2

kotykmax [81]

Answer:

Step-by-step explanation:

$12(x-2)+3x = \frac{1}{2}(x+6)+2\\\\12*x-12*2+3x=\frac{1}{2}x+\frac{1}{2}*6+2\\\\12x - 24+3x =\frac{1}{2}x+1*3+2\\\\15x - 24 = \frac{1}{2}x+3+2\\\\15x-24=\frac{1}{2}x+5\\\\15x-\frac{1}{2}x-24=5\\\\\frac{15*2}{1*2}x-\frac{1}{2}x=5+24\\\\\frac{30}{2}x-\frac{1}{2}x=29\\\\\frac{29}{2}x=29\\\\x=29*\frac{2}{29}\\\\x=2$

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3 years ago

The cost of renting a car is $ 30 /week plus $ 0.25 /mi travelled during that week. An equation to represent the cost would be y

julsineya [31]

Answer:

Amount charged for 35 miles is $ 38.75

If amount charged is $ 42.50 then distance travelled is 50 miles

Step-by-step explanation:

Equation that represents the cost is $y=30+0.25x$

Here,

x denotes the number of miles

$ 30 is the amount of rent per week

$ 0.25 is amount charged for 1 mi

To find cost if distance travelled is 35 miles, put $x=35$ in $y=30+0.25x$

Cost (y) = $30+0.25(35)=\$38.75$

So,

Amount charged for 35 miles is $ 38.75

To find number of miles for which amount charged is $ 42.50, put $y=42.50$ in $y=30+0.25x$

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So,

if amount charged is $ 42.50 then distance travelled is 50 miles.

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3 years ago

Write the equation in function form<br> 6y - 4x = 24

k0ka [10]

Answer:

f(x) = (2/3)x + 4

Step-by-step explanation:

An equation in function is found by isolating y, and changing "y" to "f(x)".

Isolate y by moving everything else to the other side

What is done to one side must be done to the other

6y - 4x = 24

6y - 4x + 4x = 24 + 4x (add 4x to both sides. -4x +4x cancels out)

6y = 24 + 4x

6y/6 = 24/6 + 4x/6 (divide both sides by 6)

y = 4 + (2/3)x (simplify)

y = (2/3)x + 4 (rearrange to a familiar format "y=mx+b")

f(x) = (2/3)x + 4 (replace y with f(x))

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3 years ago

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3 years ago

For ΔABC, which two relationships are true?

Phoenix [80]

The two correct relationships are:

$cos(\theta)=\frac{AB}{AC} = sin(90-\theta)\\\\sin(\theta)=\frac{BC}{AC} = cos(90-\theta)$

<h3>What is a right-angled triangle?</h3>

The triangle shown is a right-angled triangle

Considering < $(90-\theta)^o$

$cos(90-\theta)=\frac{BC}{AC} \\\\sin(90-\theta)=\frac{AB}{AC}\\\\tan(90-\theta)=\frac{AB}{BC}$

Considering < $\theta$

$cos(\theta)=\frac{AB}{AC} \\\\sin\theta)=\frac{BC}{AC}\\\\tan(\theta)=\frac{BC}{AB}$

Comparing < $\theta$ and < $(90-\theta)^o$ , the true statements are:

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Learn more on trigonometry here: brainly.com/question/20519838

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2 years ago