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SCORPION-xisa [38]
3 years ago
15

Please help with this question. The length of a jogging trail is 3528 m. A jogger wants to complete the trail within 30 min.

Mathematics
2 answers:
dimulka [17.4K]3 years ago
8 0
I'm confused, the answers are larger than the trail?
Fiesta28 [93]3 years ago
8 0

the correct answer would be your last one, 117 and 3/5

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$63,000 is what percent of $90,000?
alukav5142 [94]

Answer:

70%

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
How do you do the last two questions?
Mashutka [201]

Answer:

P = 6200 / (1 + 5.2e^(0.0013t))

increases the fastest

Step-by-step explanation:

dP/dt = 0.0013 P (1 − P/6200)

Separate the variables.

dP / [P (1 − P/6200)] = 0.0013 dt

Multiply the left side by 6200 / 6200.

6200 dP / [P (6200 − P)] = 0.0013 dt

Factor P from the denominator.

6200 dP / [P² (6200/P − 1)] = 0.0013 dt

(6200/P²) dP / (6200/P − 1) = 0.0013 dt

Integrate.

ln│6200/P − 1│= 0.0013t + C

Solve for P.

6200/P − 1 = Ce^(0.0013t)

6200/P = 1 + Ce^(0.0013t)

P = 6200 / (1 + Ce^(0.0013t))

At t = 0, P = 1000.

1000 = 6200 / (1 + C)

1 + C = 6.2

C = 5.2

P = 6200 / (1 + 5.2e^(0.0013t))

You need to change the exponent from negative to positive.

The inflection points are where the population increases the fastest.

5 0
3 years ago
Really need help with this pls help!!
worty [1.4K]

Let's carry this math sentence over to its natural, "shapey" element. We're going to look at each term not as an ordinary number, but as <em>the area of some shape</em>.

x² (read as "x <em>squared"</em>) can be seen as the area of a square with side lengths of x. 2x can similarly be seen as the area of a <em>rectangle </em>with a length of x and a width of 2. (Picture 1)

What's our question actually asking, though? Something about <em>perfect squares</em>. More specifically, we're looking for something to add on that'll <em>make this thing a perfect square</em>. We're trying to find a missing piece we can slot in to make a square, in other words. Problem is, our shapes don't look much like a square if we put them together right now. We need to do a little cutting and gluing first.

First, we're gonna cut the 2x rectangle lengthwise, getting two rectangles with an area of x, a length of 1, and a width of x. Next, we're going to attach them to the x² square, creating this shape that looks, strangely, like a square with a little bit missing from it (picture 2). What we're trying to do is <em>complete this square, </em>to find the area of that little missing chunk.

As it turns out, we have all the information we need for this. Notice that, using the lengths of the x rectangles, we can find that the square's dimensions are 1 x 1, which means that its area is 1 x 1  = 1.

If we tack this new area on to our original expression, we've "completed the square!" We now have a perfect square with side lengths of (x + 1) and an area of (x + 1)² (picture 3).

So, our final expression is x² + 2x + 1, and the missing constant - the area of the "missing square" we had to find to complete our larger one - is 1.

5 0
3 years ago
Read 2 more answers
8775 find the prime factorization of the number
OLEGan [10]

8775

/     \

3     2925

/       \

3      975

/       \

3      325

/       \

5      65

/       \

5      13

/       \

13      1


Prime Factors: 3, 3, 3, 5, 5, 13

5 0
3 years ago
(5x²+2) - (-4x²+7)+(-3x²-5)
svp [43]

Answer:

6x^2   -10

Step-by-step explanation:

(5x²+2) - (-4x²+7)+(-3x²-5)

Distribute the minus sign

(5x²+2) +4x²-7 +(-3x²-5)

Combine like terms

5x²+4x²-3x²  +2-7-5

6x^2              -10

6 0
3 years ago
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