Question

WILL GIVE BRAINLIEST!

Answer 1

Answer:

$Average\:Rate\:Change=-59.4$

Step-by-step explanation:

The given function is $f(x)=120(0.1)^x$.

We want to find the average rate of change of this function from $x=0$ to $x=2$.

This is given by:

$Average\:Rate\:Change=\frac{f(2)-f(0)}{2-0}$

This implies that;

$Average\:Rate\:Change=\frac{120(0.1)^2-120(0.1)^0}{2-0}$

$Average\:Rate\:Change=\frac{120(0.1)^2-120}{2}$

$Average\:Rate\:Change=\frac{120((0.1)^2-1)}{2}$

$Average\:Rate\:Change=\frac{60(0.01-1)}{1}$

$Average\:Rate\:Change=60(-0.99)$

$Average\:Rate\:Change=-59.4$