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faltersainse [42]
3 years ago
14

Is the following function an even function, odd function, or neither?

Mathematics
1 answer:
expeople1 [14]3 years ago
3 0

Answer:

I think neither but i suggest you not take my word for it.

Step-by-step explanation:

You might be interested in
Joe is building a post for his mailbox. To find the correct dimensions, he needs to expand this expression: (x-3) (x-9) (x-4) Se
kolbaska11 [484]

Answer:

(x-3)(x-9)(x-4)=x^3-16x^2+75x-108

Step-by-step explanation:

Given:

The expression to expand is given as:

(x-3)(x-9)(x-4)

Let us expand the first two binomials of the given expression using FOIL method.

The FOIL method states that:

(a + b)(c + d) = ac + ad + bc + bd

(x-3)(x-9)=(x\times x)+(x\times -9)+(-3\times x)+(-3\times -9)\\\\(x-3)(x-9)=x^2-9x-3x+27=x^2-12x+27

Now, let us multiply the result with the remaining binomial. Multiplying each term of the trinomial with each term of the binomial, we get:

(x^2-12x+27)(x-4)\\\\= (x^2\times x)+ (x^2\times -4)+(-12x\times x)+(-12x\times -4)+(27\times x)+(27\times -4)\\\\=x^3-4x^2-12x^2+48x+27x-108\\\\=x^3-16x^2+75x-108...........(\because-12x^2-4x^2=-16x^2,48x+27x=75x)

Therefore, the equivalent expression after expanding is given as:

(x-3)(x-9)(x-4)=x^3-16x^2+75x-108

3 0
3 years ago
Is t-8=3t+1 a solution , no solution or a infinite solution
olasank [31]
T = -4.5

Answer is One solution.
3 0
3 years ago
9.48 as a mixed number in simplist form
mafiozo [28]

Answer:

<h2>9 12/25.</h2>

Step-by-step explanation:

9.48 as a mixed number in simplest form:

<em><u>948/100</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4= 237/25</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4= 237/25= 9 12/25</u></em>

<u>9 12/25 is the mixed number.</u>

8 0
3 years ago
Consider a normal distribution curve where 90-th percentile is at 20 and the 25-th percentile is at 10. use this information to
ivann1987 [24]
The 25th percentile corresponds to z ≈ -0.67.
The 90th percentile corresponds to z ≈ 1.28.
So, you can write two equations in μ and σ as here:
.. μ -0.67σ = 10
.. μ +1.28σ = 20

The solution is
.. μ ≈ 13.45
.. σ ≈ 5.11

5 0
3 years ago
Smallest Zero of f(x+5)=x^2+3x+30
WARRIOR [948]
Hey there
_________________
The correct answer is:
f(x+5)=(x+5)^2+3(x+5)-10

f(x+5)=x^2+10x+25+3x+15-10

f(x+5)=x^2+13x+30  and f(x+5)=x^2+kx+30 so

k=13

Now factor x^2+13x+30

Find j and k such that jk=ac=30 and j+k+b=13 so j and k are 10 and 3 so

(x+3)(x+10)

So the two zeros occur when x=-3 and -10 the smallest of which is:

x=-10

___________________________
Hope this helps you
3 0
3 years ago
Read 2 more answers
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