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Mumz [18]
4 years ago
9

What is the Roman numeral that should be used in the following: silver (_______) sulfide? A. No Roman numeral should be used her

e. B. I C. III D. II
Chemistry
2 answers:
Ratling [72]4 years ago
4 0

Answer: The correct answer is Option B.

Explanation: The compound given to us is Ag_2S. To write the IUPAC name for this compound, we need to follow some rules:

1. First write the name of the cation with its oxidation state in roman numbers.

2. Then write the name of the anion which may be a polyatomic ion or a non-metal.

3. The anion is used with a suffix '-ide'. Example: For chlorine, the anion would be named as chloride, for sulfur, the anion would be sulfide.

For the given compound, 2 silver atoms are needed to neutralize the charge on 1 sulfur atom.

Hence, the oxidation number of silver atom is '1'. So, the IUPAC name for the compound will be silver (I) sulfide.

Therefore, the correct option is B.

Fittoniya [83]4 years ago
3 0
The answer is I

The correct way of writing this would be silver(I) sulfide, but silver sulfide without the (I) is also OK because it isn't always writte, nor is it necessary to write the (I). 
 
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Explanation:

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In wich situation can a mixture always be called a solution
weeeeeb [17]
A mixture can always be called a solution when its homogeneous.
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When 1000 C of charge is passed through CuSO4 solution, x g of copper is deposited. How much charge should be passed through the
Stels [109]

Number of charge = 5018 C

<h3>Further explanation</h3>

Given

1000 C of charge for x grams of copper

Required

Number of charge

Solution

Faraday's Law :

\tt W=\dfrac{e.i.t}{96500}\\\\W=\dfrac{e.Q}{96500}

For 1000 C, W = x grams

\tt x=\dfrac{1000.e}{96500}=0.0104e

For 5x grams :

\tt 5x=\dfrac{e.Q}{96500}\\\\5\times 0.0104e=\dfrac{e.Q}{96500}\\\\Q=\dfrac{96500\times 5\times 0.0104e}{e}=5018~C

6 0
3 years ago
At a certain temperature, the solubility of strontium arsenate, Sr3(AsO4)2, is 0.0540 g/L. What is the Ksp of this salt at this
blondinia [14]
 <span>Get into moles first. .0590 grams over 540.8 grams per mole = 1.09 x l0^-4 moles 

Sr3(As04)2 = 3 Sr++(aq) plus 2 As04^-3(aq) 

Ksp = (Sr++)^3(As04^-3)^2 

(Sr++) = 3 X l.09 x l0^-4 = 3.27 x l0^-4 

(As04^-3) = 2 x l.09 x l0^-4 = 2.18 x l0^-4 

<span>Ksp = (3.27 x l0^-4)^3 (2.18 x l0^-4)^2 which equals 1.66 x 10^-18th


I hope my answer has come to your help. Thank you for posting your question here in Brainly.</span></span>
7 0
3 years ago
The amount of energy needed to heat 6.2 g of a substance from 50.0°C to 80.0°C is 27.4 J. What is the specific heat capacity of
taurus [48]

Answer:

The heat capacity for the sample is 0.913 J/°C

Explanation:

This is the formula for heat capacity that help us to solve this:

Q / (Final T° - Initial T°) = c . m

where m is mass and c, the specific heat of the substance

27.4 J / (80°C - 50°C) = c . 6.2 g

[27.4 J / (80°C - 50°C)] / 6.2 g = c

27.4 J / 30°C . 1/6.2g = c

0.147 J/g°C = c

Therefore, the heat capacity is 0.913 J/°C

7 0
3 years ago
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