Mass percentage of a solution is the amount of solute present in 100 g of the solution.
Given data:
Mass of solute H2SO4 = 571.3 g
Volume of the solution = 1 lit = 1000 ml
Density of solution = 1.329 g/cm3 = 1.329 g/ml
Calculations:
Mass of the given volume of solution = 1.329 g * 1000 ml/1 ml = 1329 g
Therefore we have:
571.3 g of H2SO4 in 1329 g of the solution
Hence, the amount of H2SO4 in 100 g of solution= 571.3 *100/1329 = 42.987
Mass percentage of H2SO4 (%w/w) is 42.99 %
Answer:
Option (C) 4.5 liters
Explanation:
1mole of a gas occupy 22.4L at stp.
This implies that 1mole of He also occupy 22.4L at stp.
From the question given, we were asked to find the volume occupied by 0.20 mole of He at STP. This can be achieved by doing the following:
1mole of He occupied 22.4L.
Therefore, 0.2mol of He will occupy = 0.2 x 22.4L = 4.48 = 4.5L
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Some processes including enzymes. Such as enzymes working in the stomach acid prefer a pH level of 2. If higher the enzymes don't work as efficiently.
