Explanation:
A photon is a quantum of EM radiation. Its energy is given by E = hf and is related to the frequency f and wavelength λ of the radiation by
E=hf=hcλ(energy of a photon)E=hf=hcλ(energy of a photon),
where E is the energy of a single photon and c is the speed of light. When working with small systems, energy in eV is often useful. Note that Planck’s constant in these units is h = 4.14 × 10−15 eV · s.
Since many wavelengths are stated in nanometers (nm), it is also useful to know that hc = 1240 eV · nm.
These will make many calculations a little easier.
All EM radiation is composed of photons. Figure 1 shows various divisions of the EM spectrum plotted against wavelength, frequency, and photon energy. Previously in this book, photon characteristics were alluded to in the discussion of some of the characteristics of UV, x rays, and γ rays, the first of which start with frequencies just above violet in the visible spectrum. It was noted that these types of EM radiation have characteristics much different than visible light. We can now see that such properties arise because photon energy is larger at high frequencies.
Answer:
There are eight shared electron pairs.
Explanation:
The enthalpy change for the reaction 2K + S + K2S using the following thermochemical reactions is mathematically given as
dn=70.7kg
<h3>What is the enthalpy change for the reaction?</h3>
Generally, the equation for the Chemical reaction is mathematically given as
2k+s----->K2S
Therefore
KS+K----->K2S
Therefore
dn=dn1+dn2
dn=32.5+38.2
dn=70.7kg
In conclusion, the enthalpy change is
dn=70.7kg
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Answer:
jjjjjj*shhhhh is not good enough
Explanation:
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Answer: A hydrate is found to have the following percent composition: 48.8% MgSO4 and 51.2% water.
Explanation:
i dont know
