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svetoff [14.1K]
3 years ago
7

The pH of a fruit juice is 4.7. Find the hydronium ion​ concentration, [Upper H 3 Upper O Superscript plus ]​, of the juice. Use

the formula pHequalsnegative log [Upper H 3 Upper O Superscript plus ].
Chemistry
2 answers:
aksik [14]3 years ago
8 0

Answer:

Explanation:

Given:

pH = 4.7

But,

pH = -log[H3O+]

[H3O+] = 10^-pH

[H3O+] = 10^-4.7

= 1.995 × 10^-5

= 2 × 10^-5 M.

Mrrafil [7]3 years ago
7 0

Answer:

1.995*10⁻⁵

Explanation:

pH = 4.7

[H₃O⁺] = ?

pH = -log[H₃O⁺]

4.7 = -log[H₃O⁺]

Take the anti-log of both sides,

[H₃O⁺] = 10⁻⁴·⁷

[H₃O⁺] = 1.995*10^-⁵

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If we mix 25 grans if sodium oxide with a large amount of potassium chloride, how many grams of sodium chloride should be produc
amid [387]

Answer:

47.2 g

Explanation:

Data given:

mass of Sodium oxide (Na₂O) = 25 grams

mass of potassium chloride (KCl) = excess

amount of sodium chloride (NaCl) = ?

Solution:

First we look for reaction of sodium oxide with potassium chloride.

                    Na₂O + 2 KCl -----------> 2 NaCl + K₂O

As we know that potassium chloride is in excess amount and sodium oxide is 25 g so it means sodium oxide is a limiting reactant and amount of sodium chloride depends on the amount of sodium oxide.

So, now we will look for mole mole ration of Na₂O to NaCl.

                    Na₂O + 2 KCl -----------> 2 NaCl + K₂O

                    1 mol                              2 mol

from above equation we come to know that 1 mole of Na₂O gives 2 moles of NaCl.

Now convert moles to mass

As we Know

Molar mass of Na₂O = 2(23) + 16 = 62 g/mol

Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol

So

                  Na₂O              +   2 KCl    ----------->      2 NaCl          +      K₂O

             1 mol (62 g/mol)                                   2 mol (58.5 g/mol)

                  62 g                                                          117 g

So, it means that 62 g of Na₂O produce 117 g of NaCl then how many grams of NaCl will be produce by 25 g of Na₂O

Apply unity formula

                           62 g of Na₂O ≅ 117 g of NaCl

                           25 g of Na₂O ≅ X g of NaCl

Do cross multiplication

                          X g of NaCl = 117 g x 25 g / 62 g

                          X g of NaCl = 47.2 g

So,

25 g of Na₂O gives 47.2 grams of NaCl.

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