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const2013 [10]
2 years ago
14

Evaluate the temputure formula f=1.8C + 32 for C=40

Mathematics
2 answers:
neonofarm [45]2 years ago
5 0
Answer:
f=104

Explanation:
We are given the formula:
f=1.8C+32
This is a temperature formula. We want to find the degrees Fahrenheit for 40 degrees Celsius. Plug 40 in for C.
f=1.8C+32 (C=40)
f=1.8(40)+32
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Division, Addition, Subtraction.
Multiply 1.8 and 40
f=72+32
Add 72 and 32.
f=104

When C=40, f=104. So, 40 degrees Celsius is equal to 104 degrees Fahrenheit.
sweet-ann [11.9K]2 years ago
3 0

Answer:

1.8 × 40 + 32 = 104

if i got it wrong than your teacher is on crack

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What is the best approximation of the projection of (5,-1) onto (2,6)?
Hatshy [7]

Answer:

Hence, the scalar projection of \vec a onto \vec b= \frac{\sqrt{10} }{5}, and  the vector projection of \vec a onto \vec b = \frac{1}{5} \hat i+\frac{3}{5} \hat j.

Step-by-step explanation:

We have given two points  (5, -1) and (2, 6).

Let,     \vec a=5\hat {i}-\hat {j}  and  \vec b= 2\hat {i}+6\hat{j} .

and we have calculate the projection of \vec a onto \vec b.

Now,

For the calculation of projection, first we need to calculate the dot product of  \vec a  and \vec b.

\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})

     =10-6

     =4

then, we have to calculate the magnitude of \vec b.

   \mid {\vec {b}}\mid = \sqrt{2^{2}+6^{2}  } = \sqrt{40} = 2\sqrt{10}.

Now, the scalar projection of \vec a onto \vec b = \frac{\vec a.\vec b}{\mid b\mid}

                                                                 = \frac{4}{2\sqrt{10} }\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}

and the vector projection of \vec a onto \vec b = \frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b

                                                               = \frac{4}{40} . (2\hat i+ 6\hat j)

                                                                = \frac{1}{5} \hat i+\frac{3}{5} \hat j

Hence, the scalar projection of \vec a onto \vec b= \frac{\sqrt{10} }{5}, and  the vector projection of \vec a onto \vec b = \frac{1}{5} \hat i+\frac{3}{5} \hat j.

                                                               

6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bg%7D%7B3%7D%20%20%2B%207%20%3D%2019" id="TexFormula1" title=" \frac{g}{3} + 7 =
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Answer:

g = 36

Step-by-step explanation:

We have the equation \frac{g}{3} + 7 =19

Subtract 7 from both sides: \frac{g}{3} = 19 - 7 = 12

\frac{g}{3} = 12

Now, multiply by 3 to both sides: 3 × \frac{g}{3} = 3 × 12

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4 0
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