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V125BC [204]
3 years ago
14

The sum of Juanita’s age and Sara’s age is 33 years. If Sara is 15, how old is Juanita?

Mathematics
2 answers:
marissa [1.9K]3 years ago
5 0
I would assume it's 18.
astraxan [27]3 years ago
4 0
Juanita is 18 years old.
33-15
18

Hope this helps
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The height is 1.25...
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Help what is the area of this^^​ AND HOW DID YOU DO IT SHOW TOUR STRATEGY
lianna [129]

Answer:

784 cm

Step-by-step explanation:

7*8=56

24*8=192

24*7=168 168*2=336

7^{2}+24^{2}=625 \sqrt{625}=25 25*8 = 200

56+192+336+200=784

8 0
3 years ago
What is the simplified ratio of female to male students in a class, if there are 18 boys and 9 girls?
NNADVOKAT [17]
9:18 = 1:2
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8 0
2 years ago
Can you help me graph and list the (Zeros, Maximums, Minimums, Asymptotes)
Marina86 [1]

The zero of the function is at 33.69 degree , the graph is plotted and attached with the answer.

<h3>What is a Function ?</h3>

A function is a law that relates a dependent variable and an independent variable with each other

It is given that

y = 2tan (x - π/2) +3

To find the zeroes of a function that function has to be equated to zero.

2tan (x - π/2) +3 = 0

2tan (x - π/2)  = -3

tan (x - π/2)  = -3/2

x - 90 = -56.31

x = 33.69 degree

The zero of the function is at 33.69 degree

For finding the maxima /minima

the derivative is

dy/dx = 2 sec² (x - π/2)

the point at which the slope is zero is substituted in the second derivative to find maxima/minima

d²y/dx² = 4 sec² (x - π/2) tan (x - π/2)

if the value is negative then it is a maxima and if it is positive it is a minima.

The vertical asymptote is found by finding the values that make the function undefined

x = 0+ πn

No horizontal or oblique asymptote

To know more about Function

brainly.com/question/12431044

#SPJ1

5 0
1 year ago
Combine like terms: 3p2q2-3p2q3+4p2q3-3p2q2+pq PLEASE HELP!!! ASAP!!!
ch4aika [34]

Answer:

p²q³ + pq and pq(pq² + 1)

Step-by-step explanation:

Given

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Required

Collect like terms

We start by rewriting the expression

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Collect like terms

3p²q² -3p²q² - 3p²q³ +4p²q³ + pq

Group like terms

(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq

Perform arithmetic operations on like terms

(0) - (-p²q³) + pq

- (-p²q³) + pq

Open bracket

p²q³ + pq

The answer can be further simplified

Factorize p²q³ + pq

pq(pq² + 1)

Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)

7 0
3 years ago
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