Answer:
yes
Step-by-step explanation:
8² + 15² = 17²
64 + 225 = 289
289 = 289
Answer:
see below
Step-by-step explanation:
Dosage= 500 mg
Frequency= twice a day (every 12 hours)
Duration= 10 days
Number of dosage= 10*2= 20
residual drug amount after each dosage= 4.5%
We can build an equation to calculate residual drug amount:
d= 500*(4.5/100)*t= 22.5t, where d- is residual drug, t is number of dosage
After first dose residual drug amount is:
After second dose:
As per the equation, the higher the t, the greater the residual drug amount in the body.
Maximum residual drug will be in the body:
- d= 20*22.5= 450 mg at the end of 10 days
Maximum drug will be in the body right after the last dose, when the amount will be:
PEMDAS.
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction
Lets apply that here.
72-[(3x2^3)+48]
So first we start with (3x2^3)
2^3=8
3*8=24
now we do 24+48 which equals 72
now we have 72-72 which equals zero.
So
72-[(3x2^3)+48] = 0
The first step to solve this problem is to convert the first mixed number to an improper fraction.
![\frac{4}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B3%7D%20)
÷ 3 +
![\frac{1}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20)
Dividing is equivalent to multiplying with the reciprocal value,, so next you will need to change the signs.
![\frac{4}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B3%7D%20)
x
![\frac{1}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20)
+
![\frac{1}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20)
Multiply the fractions
![\frac{4}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4%7D%7B9%7D%20)
+
![\frac{1}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B3%7D%20)
Finally,, add the two fractions together to get your final answer
![\frac{7}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B7%7D%7B9%7D%20)
This means that the correct answer to your question is
![\frac{7}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B7%7D%7B9%7D%20)
.
Let me know if you have any further questions
:)