The exponential function that passes through (0,2) and (3,54) is a growth function
The exponetial function is y = 2 * 3^x
<h3>How to construct the exponential function?</h3>
The points are given as:
(x,y) = (0,2) and (3,54)
An exponential function is represented as:
y = ab^x
Substitute the points in the equation
2 = ab^0 and 54 = ab^3
Solve 2 = ab^0
a = 2
Substitute 2 for a in 54 = ab^3
54 = 2b^3
Divide by 2
27 = b^3
Take the cube roots of both sides
b = 3
So, we have:
y = ab^x
This becomes
y = 2 * 3^x
Hence, the exponetial function is y = 2 * 3^x
Read more about exponential functions at:
brainly.com/question/24077767
Answer:
x= 29/11 or y= 25/11
Step-by-step explanation:
2x - y= 3 ...........equation 1
x + 5y= 14 ............equation 2
Make x the subject of the formula in equation 2
x= 14 - 5y ..............equation 3
Substitute x=14 - 5y in equation 1
2(14- 5y) - y=3
28 - 10y - y=3
Collect like terms
-10y - y=3 - 28
-11y= -25
divide both sides by coefficient of y
-11y/-11 = -25/-11
y= 25/11
Substitute y= 25/11 in equation 3
x=14 - 5(25/11)
x= 14 - 125/11
x= 29/11
<span>{(–1, 3), (5, 3), (–6, 7), (9, 0)} is the correct answer.
I hope this helped!
</span>
Answer:
B.
Step-by-step explanation:
Have a good day i hope this helps :)
