Question

Use the set of data to calculate the measures that follow.

Answer 1

Answer:

Mean=3.5

Median=3.5

Range=6

Interquartile=1

Hope this help

Answer 2

Answer:

Mean=3.5

Median=3.5

Range=6

Interquartile=1

Step-by-step explanation:

Given set of data is 0, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6

To find Mean , Median , Range and Interquartile range :

First finding Mean

• $Mean=\frac{sum of the observations}{number of observations}$
• $=\frac{0+2+3+3+3+3+3+4+4+4+4+5+5+6}{14}$
• $=\frac{49}{14}$
• $=\frac{7}{2}$
• $=3.5$

Therefore Mean=3.5

Median:

• Since the number of observations is even, so the meadian becomes
• $Median=\frac{sum of the two mid terms}{2}$
• $=\frac{3+4}{2}$
• $=\frac{7}{2}$
• $=3.5$

Therefore Median=3.5

Range:

• Range=greatest value-least value
• In the given observations we have greatest value is 6 and least value is 0
• Therefore Range=6-0

Therefore Range=6

Interquartile:

• From the observations we have $Q_1=3$ and $Q_3=4$
• $Interquartile=Q_3-Q_1$
• $=4-3$

Therefore Interquartile=1