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blondinia [14]
3 years ago
8

Use the set of data to calculate the measures that follow.

Mathematics
2 answers:
Anna007 [38]3 years ago
5 0

Answer:

Mean=3.5

Median=3.5

Range=6

Interquartile=1

Hope this help

zepelin [54]3 years ago
3 0

Answer:

<h3>Mean=3.5</h3><h3>Median=3.5</h3><h3>Range=6</h3><h3>Interquartile=1</h3>

Step-by-step explanation:

Given set of data is 0, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 6

<h3>To find Mean , Median , Range and Interquartile range :</h3>

First finding Mean

  • Mean=\frac{sum of the observations}{number of observations}
  • =\frac{0+2+3+3+3+3+3+4+4+4+4+5+5+6}{14}
  • =\frac{49}{14}
  • =\frac{7}{2}
  • =3.5
<h3>Therefore Mean=3.5</h3><h3>Median:</h3>
  • Since the number of observations is even, so the meadian becomes
  • Median=\frac{sum of the two mid terms}{2}
  • =\frac{3+4}{2}
  • =\frac{7}{2}
  • =3.5
<h3>Therefore Median=3.5</h3><h3>Range:</h3>
  • Range=greatest value-least value
  • In the given observations we have greatest value is 6 and least value is 0
  • Therefore Range=6-0
<h3>Therefore Range=6</h3><h3>Interquartile:</h3>
  • From the observations we have Q_1=3 and Q_3=4
  • Interquartile=Q_3-Q_1
  • =4-3
<h3>Therefore Interquartile=1</h3><h3 />
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tia_tia [17]

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