<span>h<span>(t)</span>=<span>t<span>34</span></span>−3<span>t<span>14</span></span></span>
Note that the domain of h is <span>[0,∞]</span>.
By differentiating,
<span>h'<span>(t)</span>=<span>34</span><span>t<span>−<span>14</span></span></span>−<span>34</span><span>t<span>−<span>34</span></span></span></span>
by factoring out <span>34</span>,
<span>=<span>34</span><span>(<span>1<span>t<span>14</span></span></span>−<span>1<span>t<span>34</span></span></span>)</span></span>
by finding the common denominator,
<span>=<span>34</span><span><span><span>t<span>12</span></span>−1</span><span>t<span>34</span></span></span>=0</span>
<span>⇒<span>t<span>12</span></span>=1⇒t=1</span>
Since <span>h'<span>(0)</span></span> is undefined, <span>t=0</span> is also a critical number.
Hence, the critical numbers are <span>t=0,1</span>.
I hope that this was helpful.
It is:
40+1+0.3+0.02=41.32
Answer:
<h2>
John has $15 and Alex has $33</h2>
Step-by-step explanation:
a systems of equations can be made from the information on the problem
x+y=48
x=2y+3
since x= 2y+3 substitute 2y+3 in the firat equation to get:
(2y+3)+y=48 -> 3y+3=48 -> 3y=45 -> y=15
plug in 15 for y in the second equation to solve for x
x+15 =48 --> x=33