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Andreas93 [3]
3 years ago
14

At a local park, Jared can choose between two circular paths to ride his bicycle. One path has a diameter of 240 yards, and the

other has a radius of 380 yards. Jared is curious about two things. He wants to know how much farther he can ride his bike on the longer path than the shorter path if he rides his bike around the path once? Jared also wants to know how big of an area each circle covers. Use 3.14 for π.
Part A: Using the formula for circumference, find the circumference of both paths. (4 points)
Part B: Use the formula for area and solve for the area of each circle. (4 points)
Part C: How much farther can he ride his bike on the longer path if he goes around one time? (2 points)
Mathematics
2 answers:
amid [387]3 years ago
4 0

Answer:

94.2 yards

Step-by-step explanation:

1st path = d = 120 yards

c= pie d

c= 376.8 yards

2nd yard = r = 45 yards

c = 2 pie r

c = 2(3,14)(45)

c = 282.6 yards

then subtract yard 1 and yard 2 to get 94.2 yard

ANSWER :94.2 yards

nikitadnepr [17]3 years ago
4 0

Answer:

im lost

Step-by-step explanation:

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Answer:

  • 10 dimes and 4 quarters

Step-by-step explanation:

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<u>Equations according the given:</u>

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<u>Solve for q by substitution:</u>

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<u>Find the value of d:</u>

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3 years ago
Use a calculator to find the approximate value of the expression. Round the answer to two decimal places. The cosine of the comp
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B) 0.85

Step-by-step explanation:

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3 years ago
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Which statements about the graph of the function f(x) = –x2 – 4x + 2 are true? Check all that apply.
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<span>FALSE - The domain is all real numbers
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A deck of 52 cards contains 12 picture cards. If the 52 cards are distributed in a random manner among four players in such a wa
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Answer:

The probability that each player will receive three picture cards = 0.0324

Step-by-step explanation:

As given,

A deck of 52 cards contains 12 picture cards

Remaining card = 52 - 12 = 40

So,

Total number of ways in which 12 picture card is distributed = \frac{12!}{3! 3! 3! 3!}

Now,

The Total number of ways in which Remaining cards are distributed = \frac{40!}{10! 10! 10! 10!}

So,

Total number of ways of getting 3 picture card and remaining card = \frac{12!}{3! 3! 3! 3!}× \frac{40!}{10! 10! 10! 10!}

= \frac{12! 40!}{(3!)^{4} (10!)^{4}  }

Now,

Total number of ways to distribute 52 cards so that each people get 13 card = \frac{52!}{13! 13! 13! 13!} = \frac{52!}{ (13!)^{4} }

∴ The probability = \frac{\frac{12! 40!}{(3!)^{4} (10!)^{4}  }}{\frac{52!}{(13!)^{4} }}

                            = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13!)^{4} }{ 52! }

                           = \frac{12! 40!}{(3!)^{4} (10!)^{4}  }×\frac{(13.12.11.10!)^{4} }{ 52.51.50.49.48.47.46.45.44.43.42.41.40! }

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                           = 0.0324

∴ we get

The probability that each player will receive three picture cards = 0.0324

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