Answer:
A) Isaac should get £ 10.75 in change.
B) The price of the e-scooter in the sale is £ 366.3.
Step-by-step explanation:
A) Given that Isaac buys 17 anti-pollution masks for £ 5.25 each, and he pays with five £ 20 notes, to determine how much change Isaac should get, the following calculation must be performed:
(20 x 5) - (17 x 5.25) = X
100 - 89.25 = X
10.75 = X
So Isaac should get £ 10.75 in change.
B) Given that the normal price of an e-scooter is £ 370 and, in a sale, there is 1 off the normal price of the e-scooter, to determine the price of the e-scooter in the sale the following calculation must be performed:
370 - (370 x 0.01) = X
370 - 3.7 = X
366.3 = X
Thus, the price of the e-scooter in the sale is £ 366.3.
Answer:
31/40
Step-by-step explanation:
The question is incomplete. Here is the complete question with appropriate diagram.
The circle below has an area of 314 square centimeters, and the square inside the circle has a side length of 2 centimeters.
What is the probability that a point chosen at random is in the blue region?
Given the area of the circle to be 314cm², we need to get the diameter of the circle first since the diameter of the circle is equivalent to length of the side of the square inscribed in it.
Using the formula Area of a circle = πr²
314 = 3.14r²
r² = 314/3.14
r² = 100
r = 10 cm
Diameter of the circle = 2*10 = 20 cm
Area of a square = Length * length
Area of the outer square = 20*20 = 400cm²
Area of the inner square with side length 2cm = 2*2 =4cm²
Area of the shaded region = Area of the square - Area of the inner square
= 314-4 = 310cm²
The probability that a point chosen at random is in the blue region = Area of the shaded region/total area of the outer square
= 310/400
= 31/40
They will be forming a right triangle.
long leg is the height of Lyra. 22 meters high from the entrance.
short leg is the distance of Donna. 50 meters from the entrance.
We need to solve for the hypotenuse or the range of communication.
a² + b² = c²
22² + 50² = c²
484 + 2500 = c²
2,984 = c²
√2,984 = √c²
54.63 = c
The range of communication for the two radios is 55 meters.
The answer is a -4 (-16=4x)