Answer:
I believe that the answer is 24.
Answer:
t = 51 - 25p
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
25p + 1t = 51
<u>Step 2: Solve for </u><em><u>t</u></em>
- [Subtraction Property of Equality] Subtract 25p on both sides: 1t = 51 - 25p
- Simplify: t = 51 - 25p
Given statement is "point where the perpendicular bisectors of the three sides of a triangle intersect".
Perpendicular is basically a vertical line that makes 90 degree angle with the base.
bisector means the line which divides side into two equal parts.
So perpendicular bisector in any triangle will be the line which is drawn on the side of the triangle and perpendicular to that side.
Now these perpendicular bisectors meet at some point.
That point is called circumcenter.
Hence final answer will be "circumcenter".
Givens
Let the smallest integer = x
The middle integer = x + 1
The largest integer = x + 2
Remark
The first phrase up to is says the sum of ... The key word is sum. So far you have x + x + 1 + x + 2. Simplified this comes to 3x + 3.
Two times the 2nd number is 2*(x + 1) and from that, subtract 14
2(x + 1) - 14
If you break down each phrase as I have done you will soon become very good at doing these types of problems.
So the equation looks like this.
Solution
3x + 3 = 2(x + 1) - 14 Remove the brackets.
3x + 3 = 2x + 2 - 14 Combine the like terms on the right.
3x + 3 = 2x - 12 Subtract 3 from both sides.
3x = 2x - 12 - 3
3x = 2x - 15 Subtract 2x from both sides.
3x - 2x = - 15
x = -15 <<<< Answer for smallest number.
Answer
-15
- 14
-13 Are the three numbers you seek.
We need only realize that 1(-8)(-6)=48 to see that C) is the only answer from those choices that can be an answer.
