Suppose that an airline uses a seat width of 16.7 in. Assume men have hip breadths that are normally distributed with a mean of
2 answers:
Answer:
Step-by-step explanation:
Given that X, the hip width of men is N(14.2, 0.9)
i.e. we have is N(0,1)
Seat width an airline uses = 16.7 inches.
a) the probability that if an individual man is randomly selected, his hip breadth will be greater than 16.7 in
b) Here sample size = 126
Each person is independent of the other
the probability that these men have a mean hip breadth greater than 16.7
= <0.00001
c) part a is important since even a single person not fitting will cause embarassment and leads to customer dissatisfaction.
Answer:
a) 0.003
b) 0.00001
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 14.2
Standard Deviation, σ = 0.9
We are given that the distribution of hip breadths is a bell shaped distribution that is a normal distribution.
Formula:
a) P(hip breadth will be greater than 16.7)
P(x > 16.7)
Calculation the value from standard normal z table, we have,
b) Standard error due to sampling
a) P(hip breadth will be greater than 16.7 for the sample)
P(x > 16.7)
Calculation the value from standard normal z table, we have,
c)Result in a) should be considered for any changes in seat design because we need to consider the whole population and not the result for a sample.
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