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LUCKY_DIMON [66]

3 years ago

5

Answer choices A. 42.9% B. 16.7% C. 83.3% D. 25%

1 answer:

Aleksandr [31]3 years ago

6 0

P(m) = 1/4
P(odd) = 2/3

1/4 x 2/3 = 1/6

1/6 = 16.7%

Answer is B

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Rayan bought 3 2/3 lb of apples to make

Juli2301 [7.4K]

Answer:

3.66 lb

Step-by-step explanation:

2/3=0.666

3+0.66=3.66

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2 years ago

GarryVolchara [31]

$\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{Table~A}{\begin{array}{ccll} x&y\\ \cline{1-2} 60&48\\70&56\\80&64 \end{array}}~\hspace{7em} \stackrel{Table~B}{\begin{array}{ccll} x&y\\ \cline{1-2} 20&24\\30&36\\40&48 \end{array}} \\\\[-0.35em] ~\dotfill$

$\bf \textit{for table A, we know that } \begin{cases} x=60\\ y=48 \end{cases}\implies 48=k60\implies \cfrac{48}{60}=k \\\\\\ \cfrac{4}{5}=k\qquad therefore\qquad \boxed{y=\cfrac{4}{5}x} \\\\\\ \textit{for table B, we know that } \begin{cases} x=30\\ y=36 \end{cases}\implies 36=k30\implies \cfrac{36}{30}=k \\\\\\ \cfrac{6}{5}=k\qquad therefore\qquad \boxed{y=\cfrac{6}{5}x}$

4 0

3 years ago

What is the area of the composite shape below?

Hatshy [7]

5*2=10
10+12*4.5=64cm^2

Hope it helps

5 0

3 years ago

Andrew is moving from Manhattan to Brooklyn and rented a truck from U-Haul. The cost of one-day truck rental is given by

sineoko [7]

Answer:

Assuming that Andrew made the trip in one day, the cost of the truck rental is $89

Step-by-step explanation:

You can find the answer essentially by plugging in 78 for every variable m: C(78)=0.50(78)+50

C(78)=39+50

C(78)=89

The cost of driving 78 miles in one day is $89.

8 0

3 years ago

If ∫−1−4f(x)dx=0 and ∫31g(x)dx=3, what is the value of ∫∫Df(x)g(y)dA where D is the square: −4≤x≤−1, 1≤y≤3?

Lana71 [14]

Answer:

0

Step-by-step explanation:

From your problem, we have to extract the information that are important from the first two intregrals so we can solve the double integral.

$\int\limits^{-1}_{-4} {f(x)} \, dx = 0$

We also have that:

$\int\limits^{3}_{1} {g(x)} \, dx = 3$

---------------------------------

With this, now we can solve the double integral.

Since the limits of integration are constant, i can use dA both as dydx or dxdy. I am going to use dydx.

So the double integral will be:

$\int \limits^{-1}_{-4} \int \limits^{3}_{1} {g(y)} {f(x)} dy dx\$

We solve a double integral from the inside to the outside, so the first integral we solve is:

$\int \limits^{3}_{1} \y g(y) \x f(x) dy$

f is a function of x and we are integrating dy, so this means that f is a constant. Our integral now is this:

$\x f(x) \int \limits^{3}_{1} \y g(y) dy$

From above, we have that

$\int \limits^{3}_{1} \x g(x) dx = 3$

So,

$\int \limits^{3}_{1} \y g(y) dy = 3$

Now we have to solve the outside integral:

$3\int\limits^{-1}_{-4} {f(x)} \, dx$

We know that

$\int\limits^{-1}_{-4} {f(x)} \, dx = 0$

So the double integral will be 0

3 0

3 years ago