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LUCKY_DIMON [66]
3 years ago
5

Answer choices A. 42.9% B. 16.7% C. 83.3% D. 25%

Mathematics
1 answer:
Aleksandr [31]3 years ago
6 0
P(m) = 1/4
P(odd) = 2/3

1/4 x 2/3 = 1/6 

1/6 = 16.7%

Answer is B

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Rayan bought 3 2/3 lb of apples to make
Juli2301 [7.4K]

Answer:

3.66 lb

Step-by-step explanation:

2/3=0.666

3+0.66=3.66

6 0
2 years ago
PLEAS HELP ME
GarryVolchara [31]

\bf \qquad \qquad \textit{direct proportional variation} \\\\ \textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby \begin{array}{llll} k=constant\ of\\ \qquad variation \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \stackrel{Table~A}{\begin{array}{ccll} x&y\\ \cline{1-2} 60&48\\70&56\\80&64 \end{array}}~\hspace{7em} \stackrel{Table~B}{\begin{array}{ccll} x&y\\ \cline{1-2} 20&24\\30&36\\40&48 \end{array}} \\\\[-0.35em] ~\dotfill


\bf \textit{for table A, we know that } \begin{cases} x=60\\ y=48 \end{cases}\implies 48=k60\implies \cfrac{48}{60}=k \\\\\\ \cfrac{4}{5}=k\qquad therefore\qquad \boxed{y=\cfrac{4}{5}x} \\\\\\ \textit{for table B, we know that } \begin{cases} x=30\\ y=36 \end{cases}\implies 36=k30\implies \cfrac{36}{30}=k \\\\\\ \cfrac{6}{5}=k\qquad therefore\qquad \boxed{y=\cfrac{6}{5}x}

4 0
3 years ago
What is the area of the composite shape below?​
Hatshy [7]
5*2=10
10+12*4.5=64cm^2

Hope it helps
5 0
3 years ago
Andrew is moving from Manhattan to Brooklyn and rented a truck from U-Haul. The cost of one-day truck rental is given by
sineoko [7]

Answer:

Assuming that Andrew made the trip in one day, the cost of the truck rental is $89

Step-by-step explanation:

You can find the answer essentially by plugging in 78 for every variable m: C(78)=0.50(78)+50

C(78)=39+50

C(78)=89

The cost of driving 78 miles in one day is $89.

8 0
3 years ago
If ∫−1−4f(x)dx=0 and ∫31g(x)dx=3, what is the value of ∫∫Df(x)g(y)dA where D is the square: −4≤x≤−1, 1≤y≤3?
Lana71 [14]

Answer:

0

Step-by-step explanation:

From your problem, we have to extract the information that are important from the first two intregrals so we can solve the double integral.

\int\limits^{-1}_{-4} {f(x)} \, dx = 0

We also have that:

\int\limits^{3}_{1} {g(x)} \, dx = 3

---------------------------------

With this, now we can solve the double integral.

Since the limits of integration are constant, i can use dA both as dydx or dxdy. I am going to use dydx.

So the double integral will be:

\int \limits^{-1}_{-4} \int \limits^{3}_{1} {g(y)} {f(x)} dy dx\

We solve a double integral from the inside to the outside, so the first integral we solve is:

\int \limits^{3}_{1} \y g(y) \x f(x) dy

f is a function of x and we are integrating dy, so this means that f is a constant. Our integral now is this:

\x f(x) \int \limits^{3}_{1} \y g(y) dy

From above, we have that

\int \limits^{3}_{1} \x g(x) dx = 3

So,

\int \limits^{3}_{1} \y g(y) dy = 3

Now we have to solve the outside integral:

3\int\limits^{-1}_{-4} {f(x)} \, dx

We know that

\int\limits^{-1}_{-4} {f(x)} \, dx = 0

So the double integral will be 0

3 0
3 years ago
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