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3 years ago

3x-2 less than or equal than 7

Mathematics

1 answer:

Vlad1618 [11]3 years ago

4 0

What is x equal to? We would have to find the actual value to compare. No variable.

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What is the percentage of "85% of 78.00?" (Also needs calculation)

Tatiana [17]

-21.85.999

I found the ansewr by dividing both of the numbers to equal tthat

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3 years ago

Whats the square root of 9

kolezko [41]

There are two solutions to this question, one is positive and the other is negative:
$\sqrt{9} =3\ or\ -3$

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3 years ago

How many teaspoons make up 40ml<br>

mojhsa [17]

Answer:

Convert 40 Milliliters to Teaspoons

mL tsp

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3 0

3 years ago

Read 2 more answers

Un capital de 4000 lei este plasat în regim de dobândă simplă pe o perioadă de 3 ani cu rata dobânzii

9966 [12]

Answer:

960

Step-by-step explanation:

The simple interest formula is the following:

I = P*r*t

Where I is the interest generated after t years, P is the inicial value and r is the rate of interest.

In this case, we have that the inicial value is P = 4000, the rate of interest is r = 8% = 0.08 and the amount of time invested is t = 3 years.

So, the interest will be:

I = 4000*0.08*3 = 960

3 0

3 years ago

Someone please help me with this lol… have no idea what I’m doing

Sholpan [36]

Given:

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

To find:

The quadrant of the terminal side of $\theta$ and find the value of $\sin\theta$ .

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

$\cos \theta =\dfrac{3}{5}$

$\sin \theta$

Here cos is positive and sine is negative. So, $\theta$ must be lies in Quadrant IV.

We know that,

$\sin^2\theta +\cos^2\theta =1$

$\sin^2\theta=1-\cos^2\theta$

$\sin \theta=\pm \sqrt{1-\cos^2\theta}$

It is only negative because $\theta$ lies in Quadrant IV. So,

$\sin \theta=-\sqrt{1-\cos^2\theta}$

After substituting $\cos \theta =\dfrac{3}{5}$ , we get

$\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}$

$\sin \theta=-\sqrt{1-\dfrac{9}{25}}$

$\sin \theta=-\sqrt{\dfrac{25-9}{25}}$

$\sin \theta=-\sqrt{\dfrac{16}{25}}$

$\sin \theta=-\dfrac{4}{5}$

Therefore, the correct option is B.

6 0

3 years ago