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3 years ago

Plz help!!!!!!!!!!!!!

Mathematics

2 answers:

Anvisha [2.4K]3 years ago

8 0

Answer: $\bold{c)\quad x=\dfrac{6\pm \sqrt{(-6)^2-4(3)(8)}}{2(3)}}$

<u>Step-by-step explanation:</u>

$3x^2-6x+8=0\quad \rightarrow \quad a=3,\ b=-6,\ c=8\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-6)\pm \sqrt{(-6)^2-4(3)(8)}}{2(3)}}\\\\\\x=\dfrac{6\pm \sqrt{(-6)^2-4(3)(8)}}{2(3)}$

pantera1 [17]3 years ago

5 0

Answer:

the third one

Step-by-step explanation:

-b to start is -(-6) which is 6

needs the plus and minus

the first expression is the whole numerator

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