Question

Plz help!!!!!!!!!!!!!

Answer 1

Answer:   $\bold{c)\quad x=\dfrac{6\pm \sqrt{(-6)^2-4(3)(8)}}{2(3)}}$

Step-by-step explanation:

$3x^2-6x+8=0\quad \rightarrow \quad a=3,\ b=-6,\ c=8\\\\\text{Quadratic formula is: }x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(-6)\pm \sqrt{(-6)^2-4(3)(8)}}{2(3)}}\\\\\\x=\dfrac{6\pm \sqrt{(-6)^2-4(3)(8)}}{2(3)}$

Answer 2

Answer:

the third one

Step-by-step explanation:

-b to start is -(-6) which is 6

needs the plus and minus

the first expression is the whole numerator