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bixtya [17]
3 years ago
12

Solve -5/3x + 7/3 = -5

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
3 0

Answer:

x = 24/15 = 8/3 = 2 2/3

Step-by-step explanation:

remember what you do to the left you must do to the right.

I converted the -5 to -15/3 so I could easily add or subtract

-5/3 x = -8/3

multiply both sides by -3/5 to cancel the coefficient of the x

x = -8/3 * -3/5 = 24/15

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Consider the following number line
Sati [7]

<u>Answer:</u>

<h2><u>-2.25</u></h2><h3><u>Step-by-step explanation:</u></h3>

Lets start with D:

It says, 0.43 but we're on the OPPOSITE of 0, so it can't be a positive number.

Same goes for C.

Now we are on to our last two.

B, is -2.5 and A, is -0.8

So, now we look at the point <em>B </em>and <em>assume</em>, because it says Select a reasonable value for Point B.

To me, point <em>B </em>looks to be about around -2.0

So, the <em>reasonable value </em>for this problem would be -2.25

8 0
2 years ago
NO LINKS!!
dexar [7]

Answer: Anything between 0 and 10, excluding both endpoints.

In terms of symbols we can say 0 < w < 10 where w is the width.

===================================================

Explanation:

You could do this with two variables, but I think it's easier to instead use one variable only. This is because the length is dependent on what you pick for the width.

w = width

2w = twice the width

2w-5 = five less than twice the width = length

So,

  • width = w
  • length = 2w-5

which lead to

area = length*width

area = (2w-5)*w

area = 2w^2-5w

area < 150

2w^2 - 5w < 150

2w^2 - 5w - 150 < 0

To solve this inequality, we will solve the equation 2w^2-5w-150 = 0

Use the quadratic formula. Plug in a = 2, b = -5, c = -150

w = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\w = \frac{-(-5)\pm\sqrt{(-5)^2-4(2)(-150)}}{2(2)}\\\\w = \frac{5\pm\sqrt{1225}}{4}\\\\w = \frac{5\pm35}{4}\\\\w = \frac{5+35}{4} \ \text{ or } \ w = \frac{5-35}{4}\\\\w = \frac{40}{4} \ \text{ or } \ w = \frac{-30}{4}\\\\w = 10 \ \text{ or } \ w = -7.5\\\\

Ignore the negative solution as it makes no sense to have a negative width.

The only practical root is w = 10.

If w = 10 feet, then the area = 2w^2-5w results in 150 square feet.

----------------------

Based on that root, we need to try a sample value that is to the left of it.

Let's say we try w = 5.

2w^2 - 5w < 150

2*5^2 - 5*5 < 150

25 < 150 ... which is true

This shows that if 0 < w < 10, then 2w^2-5w < 150 is true.

Now try something to the right of 10. I'll pick w = 15

2w^2 - 5w < 150

2*15^2 - 5*15 < 150

375 < 150 ... which is false

It means w > 10 leads to 2w^2-5w < 150  being false.

Therefore w > 10 isn't allowed if we want 2w^2-5w < 150 to be true.

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Answer:

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Hence recursive formula is a_n =a_{n-1} +5

Non recursive formula:

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iii) Start with 3.

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