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densk [106]
3 years ago
8

Error Analysis: Pedro compares 7/33 and 2/11. He incorrectly says 7/33 < 2/11 because 4.71 < 5.50. Compare 7/33 and 2/11.

Mathematics
1 answer:
madreJ [45]3 years ago
5 0
He divided the wrong way.  7/33 = .2121.....and 2/11 = .1818...., so actually 2/11 < 7/33
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Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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So it is z with a pvalue of 1-0.005 = 0.995, so z = 2.575

Now, find the margin of error M as such

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In which \sigma is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when M = 0.06, \sigma = 1.1

0.06 = 2.575*\frac{1.1}{\sqrt{n}}

0.06\sqrt{n} = 2.575*1.1

\sqrt{n} = \frac{2.575*1.1}{0.06}

(\sqrt{n})^{2} = (\frac{2.575*1.1}{0.06})^{2}

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Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

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So an example


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