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3 years ago

Need help urgently please

Mathematics

1 answer:

OLga [1]3 years ago

7 0

Answer:

what do you want me to do actuallt the pic is Unclear?

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Angela work on a straight 7% commission. Her friend worked on a salary of $600 plus a 10% commission. In a particular month, the

sveticcg [70]

all you need to do is change your percentages to decimal and then multiply

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3 years ago

SinA=√1-x÷√1+X<br> Find the value of cosA

Irina-Kira [14]

The value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

<h3>Trigonometric ratios</h3>

It is important to note that

sin A = opposite/ hypotenuse

cos A = adjacent/ hypotenuse

Then,

opposite = $\sqrt{1} - x$

Hypotenuse = $\sqrt{1} + x$

Let's find the adjacent side using the Pythagorean theroem

$(\sqrt{1} + x)^2 = (\sqrt{1 -x } )^2 + x^2$

$1 + x^2 = 1 - x^2 + x^2$

$x = \sqrt{\frac{1 + x^2}{1 -x^2} }$

cos A = x/hypotenuse

$cos A = \frac{\sqrt{\frac{1+x^2}{1 -x^2} } }{\sqrt{1} +x}$

cos A = √(1 + x²)/ (1 - x²) /√1 + x

Thus, the value of cos A is √(1 + x²)/ (1 - x²) /√1 + x

Learn more about trigonometric identities here:

brainly.com/question/7331447

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6 0

2 years ago

A rental car agency charges $220.00 per week plus 50.15 per mile to rent a car. How many miles can you travel in one week for $3

babymother [125]

Answer:2.81

Step-by-step explanation:

First you subtract the per week (220) from your budget (361)

You get 141

You now divide 141 by 50.15

You come out to 2.81

This means you can drive up to 2.81 miles but no more

8 0

3 years ago

Show why x−3 is a factor of m(x)=x3−x2−5x−3. Justify your answer. You can show this using remainder theorem, long division, synt

Marat540 [252]

The factors of a polynomial function are the zeros of the function

It is true that x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3

<h3>How to show why the x - 3 is a factor</h3>

The function is given as:

m(x) = x^3 - x^2 - 5x - 3

The factor is given as:

x - 3

Set the factor to 0

x - 3 = 0

Solve for x

x = 3

Substitute 3 for x in the function

m(3) = 3^3 - 3^2 - 5(3) - 3

Evaluate

m(3) =0

Since the value of m(3) is 0, then x - 3 is a factor of m(x) = x^3 - x^2 - 5x - 3