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MAVERICK [17]
4 years ago
11

Six red marbles, 4 green marbles and 2 blue marbles are placed in a jar. What is the probability of selecting a red marble and t

hen another red marble given the first marble is not returned to the jar after it is drawn?
2/11

5/22

2/33

5/33
Mathematics
1 answer:
Karolina [17]4 years ago
3 0

|\Omega|=12\cdot11=132\\ |A|=6\cdot5=30\\\\ P(A)=\dfrac{30}{132}=\dfrac{5}{22}

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Angles a and b are complementary angles symmetry of angle a is 28° more than the measure of angle b find the missing angle measu
scoray [572]

Answer:

31 , 59

Step-by-step explanation:

a = b +28

a + b = 90 {Complementary}

b + 28 + b = 90    {Combine like terms}

2b + 28 = 90       {Subtract 28 form both sides}

       2b  = 90 - 28

       2b = 62      {Divide both sides by 2}

        b = 62/2

       b = 31

a = 31 + 28

a = 59

7 0
3 years ago
Paula is going to choose the size, color, phrase, and picture for a birthday card for her friend. There are 2 sizes, 4 colors, 7
grandymaker [24]

Answer:

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
let p be the number of primes less than 100, and let Q be the number of primes less than 90. What is the value of P-Q?
3241004551 [841]

The value of P - Q as described in the question above is; P -Q = 2.

According to the question;

  • P = number of primes less than 100
  • Q = number of primes less than 90

Since, we are required to determine what the value of P-Q is;

The value of P-Q is simply the number of primes between 90 and 100.

The prime numbers between 90 and 100 are; 91 and 97.

Therefore, P - Q = 2.

Read more;

brainly.com/question/22257959

3 0
3 years ago
In rectangle $ABCD$, $AD=1$, $P$ is on $\overline{AB}$, and $\overline{DB}$ and $\overline{DP}$ trisect $\angle ADC$. Write the
Studentka2010 [4]
<h3>Answer:</h3>

w+x+y+z = 12

<h3>Explanation:</h3>

When right angle ADC is divided into three equal parts (trisected), each of those parts is 90°/3 = 30°. Thus, ∠CDB = ∠PBD = ∠PDB = 30°.

The sides of a 30°-60°-90° triangle are in the proportion 1 : √3 : 2. Hence BD = 2, and PD = PB = 2/√3 = (2/3)√3.

Then the perimeter of ∆BDP is ...

... perimeter ∆BDP = BD + DP + PB

... = 2 + (2/3)√3 + (2/3)√3

... = 2 + (4√3)/3 . . . . . . . . w=2, x=4, y=3, z=3

w + x + y + z = 2+4+3+3 = 12

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3 years ago
Levi saved 3/5 of the amount he needs to buy a $75 video game
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5 0
3 years ago
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