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ArbitrLikvidat [17]

2 years ago

10

Janet bought 5 yards of fabric 214-feet wide to make curtains. She used 13 of the fabric to make a long set of curtains and the

rest to make 4 short sets.

1 answer:

SpyIntel [72]2 years ago

8 0

Answer:

the answer is 200 feets left

Step-by-step explanation:

she only has 87 percent of the 5 yards that she bought

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If CB =3(x+8) and AD= 4(x+3), find AB

kkurt [141]

CD=CA+AB+BD

AB=CD-CA-BD

AB=CD-BD-BD

AB=CD-2.BD

AB=CD-2(BC+CD)

AB=CD-2BC-2CD

AB=-(CD+2BC)

AB=-{98-6(x+8)}

AB= 6x-50

6 0

2 years ago

Situation:A researcher in North America discoversa fossile that contains 65% of its originalamount of C-14..-ktN=NoeNo inital am

zheka24 [161]

SOLUTION

We have been given the equation of the decay as

$\begin{gathered} N=N_0e^{-kt} \\ where\text{ } \\ N_0=initial\text{ amount of C-14 at time t} \\ N=amount\text{ of C-14 at time t = 65\% of N}_0=0.65N_0 \\ k=0.0001 \\ t=time\text{ in years = ?} \end{gathered}$

So we are looking for the time

Plugging the values into the equation, we have

$\begin{gathered} N=N_0e^{-kt} \\ 0.65N_0=N_0e^{-0.0001t} \\ e^{-0.0001t}=\frac{0.65N_0}{N_0} \\ e^{-0.0001t}=0.65 \end{gathered}$

Taking Ln of both sides, we have

$\begin{gathered} ln(e^{-0.000t})=ln(0.65) \\ -0.0001t=ln(0.65) \\ t=\frac{ln(0.65)}{-0.0001} \\ t=4307.82916 \end{gathered}$

Hence the answer is 4308 to the nearest year

8 0

5 months ago

At 6:00 A.M. the temperature was 33°F. By noon the temperature had increased by 10°F and by 3:00 P.M. it had increased another 1

chubhunter [2.5K]

So let's see here...

6:00 A.M. temperature is 33°F.

12:00 P.M temperature increased by 10°F making it 43°F.

3:00 P.M. temperature increased by another 12°F making it 55°F.

At 10:00 P.M it would decrease by 15°F making it 40°F.

The temperature would need to fall (or decrease) by 7°F to reach the original temperature of 33°F

Hope this helped!

3 0

2 years ago

The measures of 5 of the Interior angles of a hexagon are: 115.125", 85", 150", and 170". What is the measure of the

levacccp [35]

The measure of the largest exterior angle of hexagon is 105

<u>Solution:</u>

Given, The measures of 5 of the Interior angles of a hexagon are: 115.125", 85", 150", and 170".

We have to find what is the measure of the largest exterior angle?

Now let us find the 6th interior angle,

We know that, sum of interior angles of hexagon = 720 degrees

115 + 125 + 85 + 150 + 170 + 6th angle = 720

645 + 6th angle = 720

6th angle = 720 – 645

6th angle = 75 degrees

Now we have to find the largest exterior angle, we know that, the complement of largest exterior angle will be smallest interior angle.

So, here smallest interior angle is 75

sum of interior and exterior angle equals to 180

Hence interior angle + exterior angle =180

Then, 75 + exterior angle = 180

Exterior angle = 180 – 75 = 105.

Hence, exterior angle is 105 and 1st option is correct.

4 0

2 years ago

Can some please help me with this one it would be much appreciated

kherson [118]

πAnswer:

Therefore, the area of a sector of a circle would be 13.5π square units.

Step-by-step explanation:

Given

$r=9$ mi

Ф = 60°

The area of a sector of a circle is:

A = π r² Ф/360

A = π (9)² 60/360

A = π 81 * 1/6

A = 13.5π square units

Therefore, the area of a sector of a circle would be 13.5π square units.

7 0

2 years ago