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3 years ago

What is the equation of the line that passes through the point (1,3)(1,3) and has a slope of -3−

Mathematics

1 answer:

timama [110]3 years ago

5 0

Answer:

y = -3x + 6

Step-by-step explanation:

First, this is your current equation: y= -3x+b. Fill in one of your coordinates into the equation (it doesn't matter which one because they're both the same). It should look like this: 3 = -3(1) + b. Multiply -3 and 1 to get -3. So, this is what it should look like: 3 = -3 + b. Add 3 to both sides to get your y-intercept of 6. Go back to your original equation and plug in 6 to b. This is your final equation: y = -3x + 6. Hope this helped!

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How to graph from linear standered form 2x-6y=12?

Alexus [3.1K]

Answer:

See graph below for answer

Step-by-step explanation:

Step 1) Change to y-intercept form

6y = 2x - 12

y = 1/3x - 2

Step 2) Graph.

See graph below for answer

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3 years ago

What multiplier do we use to increase by 72%

Deffense [45]

Answer:

1.72

Step By Step:

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3 years ago

Which of the following is not equivalent to 1/25?

taurus [48]

The answer is D. 5^-2 times 5^4.

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4 years ago

what is the acceleration of a baseball when its speed increases from 1 m/sec to 25 m/sec in 1 second?

kirill115 [55]

Answer:

24 m/s²

Step-by-step explanation:

Acceleration is change in velocity over time.

a = Δv / Δt

a = (25 m/s − 1 m/s) / 1 s

a = 24 m/s²

7 0

3 years ago

What set of reflections would carry rectangle ABCD onto itself?

Dvinal [7]

Answer:

y=x, x-axis, y=x, y-axis

Explanation:

Reflecting the figure across three axes just moves it from one quadrant to another. It does not map the figure to itself.

Reflecting across the line y=x moves it from quadrant II to IV or vice-versa. If it is in quadrant I or III, it stays there. So the sequence of reflections x-axis (moves from I to IV), y=x (moves from IV to II), x-axis (moves from II to III), y=x (stays in III) will not map the figure to itself.

However, the last selection will map the figure to itself. The initial (and final) figure location, and the intermediate reflections are shown in the attached. The figure starts and ends as blue, is reflected across y=x to green, across x-axis to orange, across y=x to red, and finally across y-axis to blue again.

7 0

3 years ago