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irinina [24]
3 years ago
6

A cargo truck weighs 8750 pounds the weight limit is 5 tons how many pounds of cargo can be added to the truck before it's at th

e limit 28;$;$&($3&:nfkdvv hv bdjfgeh
Mathematics
1 answer:
Alika [10]3 years ago
3 0

Answer:

1250 pounds.

Step-by-step explanation:

The weight of the cargo truck = 8750 pounds

Weight Limit = 5 tons

To determine what weight of cargo can  be added, we simply subtract the weight of the cargo truck from the weight limit.

First, we ensure they are both in same metric units.

Now: 1 ton = 2000 pounds

Therefore, 5 tons = 5 X 2000 = 10000 pounds.

Weight of cargo that can be added= Weight Limit-Truck Weight

=10000-8750

=1250 pounds.

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Answer:

47.52% probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth

Step-by-step explanation:

For each individual, there are only two possible outcomes. Either they cover their mouth when sneezing, or they do not. The probability of an individual covering their mouth when sneezing is independent of other individuals. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

According to a study done by Otago University, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267.

This means that p = 0.267

What is the probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth

10 individuals, so n = 10.

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)

In which

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.267)^{0}.(0.733)^{10} = 0.0448

P(X = 1) = C_{10,1}.(0.267)^{1}.(0.733)^{9} = 0.1631

P(X = 2) = C_{10,2}.(0.267)^{2}.(0.733)^{8} = 0.2673

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0448 + 0.1631 + 0.2673 = 0.4752

47.52% probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth

5 0
3 years ago
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