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diamong [38]
3 years ago
13

The sum of two numbers is 136.One number is 51.What is the the other number? What are the common factors of these two numbers

Mathematics
2 answers:
SVEN [57.7K]3 years ago
4 0
136-51=85. so the common factors would be 1 and 17
Gemiola [76]3 years ago
4 0
136
- 51
------------
85
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18^9 ÷ 18 ^4 equivalent expression
max2010maxim [7]

Answer:

18^5

Step-by-step explanation:

18^9 ÷ 18^4

= 18 ^ (9-4)

= 18 ^ 5

8 0
3 years ago
Erican System Conversions
gogolik [260]

Answer:

The answer to your question is Area = 3240 ft²   or Area = 360 yd²    

Step-by-step explanation:

Data

length = 30 yd

width = 36 ft

Area = ? ft²

Area = ? yd²

Process

1.- Convert the units

                  1 yd --------------------- 3ft

                 30 yd ------------------   x

                  x = (30 x 3)/1

                  x = 90 ft

                  1 yd ------------------- 3 ft

                  x     ------------------- 36 ft

                  x = (36 x 1) / 3

                  x = 12 yd

2.- Calculate the area of the rectangle in ft²

Area = length x width

-Substitution

Area = 90 x 36

        = 3240 ft²

3.- Calculate the area in yd²

Area = 30 x 12

        = 360 yd²                

                   

7 0
3 years ago
1. ∠E and ∠F are vertical angles with m∠E=9x+12 and m∠F=3x+24
Oduvanchick [21]
The value of x is 2 and KNL will be 102
6 0
4 years ago
What is 4m - 2m^4 - 6m^2 + 9= in standard form
valkas [14]
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8 0
3 years ago
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Lera25 [3.4K]

Answer:

212m

Step-by-step explanation:

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Using the SOH, CAH, TOA trigonometry identity to solve for the length of the rope;

Since we have the angle theta = 45° and opposite = 150m

According to SOH;

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Sin45° = 150/hyp

hyp = 150/sin45°

hyp = 150/(1/√2)

hyp = 150×√2

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hyp = 212.13m

Hence the length of the rope for the kite sail, in order to pull the ship at an angle of 45° and be at a vertical height of 150 m is approximately 212m

8 0
3 years ago
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