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diamong [38]
3 years ago
13

The sum of two numbers is 136.One number is 51.What is the the other number? What are the common factors of these two numbers

Mathematics
2 answers:
SVEN [57.7K]3 years ago
4 0
136-51=85. so the common factors would be 1 and 17
Gemiola [76]3 years ago
4 0
136
- 51
------------
85
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Use long division to divide x^3+x^2-2x+14 by x+3
bekas [8.4K]

First, x^3=x^2\cdot x, and if we multiply x+3 by x^2 we get

x^3+3x^2

Subtracting this from the numerator gives a remainder of

-2x^2-2x+14

Next, -2x^2=-2x\cdot x, and if we multiply x+3 by -2x we have

-2x^2-6x

and subtracting this from the previous remainder, we end up with a new remainder of

4x+14

Next, 4x=4\cdot x, and if we multiply x+3 by 4 we get

4x+12

Subtracting from the previous remainder, we get a new remainder of

2

which contains no more factors of x, so we're done.

So,

\dfrac{x^3+x^2-2x+14}{x+3}=x^2-2x+4+\dfrac2{x+3}

8 0
3 years ago
Write 0.111 in words ​if you want brainlist
dalvyx [7]

Answer: one hundred eleven thousandths

Step-by-step explanation:

8 0
1 year ago
Convert into slope-intercept form: <img src="https://tex.z-dn.net/?f=y-1%3Dm%28x-3%29" id="TexFormula1" title="y-1=m(x-3)" alt="
aliina [53]

Answer:

y=2x-5

Step-by-step explanation:

First simplify: y-1=2x-6

y-1=2(x-3)

First simplify and distribute everything.

<u>y-1=2x-6</u>

So, x equals 2 because it got distributed into the numbers inside the parenthesis.  Same with the 2 and -3.  They multiplied to become -6.

Since it's y-1=2x-6, you can simplify it even more so the -1 goes to the other side and turns into positive 1.

<u>y - 1 (+ 1) = 2x -6 (+ 1)</u>

-1(+1)=0 which leaves just the variable y on the <em><u>left side</u></em>.

-6(+1)=-5 which leaves 2x-5 on the <em><u>right side</u></em>.

This results in y=2x-5.  Hope this helped ;)

6 0
3 years ago
Read 2 more answers
How do you factorize p2 + 2p - 3 =0
julia-pushkina [17]

Answer:

Solution

p = {-3, 1}

Step-by-step explanation:

Simplifying

p2 + 2p + -3 = 0

Reorder the terms:

-3 + 2p + p2 = 0

Solving

-3 + 2p + p2 = 0

Solving for variable 'p'.

Factor a trinomial.

(-3 + -1p)(1 + -1p) = 0

Subproblem 1

Set the factor '(-3 + -1p)' equal to zero and attempt to solve:

Simplifying

-3 + -1p = 0

Solving

-3 + -1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '3' to each side of the equation.

-3 + 3 + -1p = 0 + 3

Combine like terms: -3 + 3 = 0

0 + -1p = 0 + 3

-1p = 0 + 3

Combine like terms: 0 + 3 = 3

-1p = 3

Divide each side by '-1'.

p = -3

Simplifying

p = -3

Subproblem 2

Set the factor '(1 + -1p)' equal to zero and attempt to solve:

Simplifying

1 + -1p = 0

Solving

1 + -1p = 0

Move all terms containing p to the left, all other terms to the right.

Add '-1' to each side of the equation.

1 + -1 + -1p = 0 + -1

Combine like terms: 1 + -1 = 0

0 + -1p = 0 + -1

-1p = 0 + -1

Combine like terms: 0 + -1 = -1

-1p = -1

Divide each side by '-1'.

p = 1

Simplifying

p = 1

Solution

p = {-3, 1}

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3 years ago
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