What is the minimum hot-holding temperature requirement for pizza?

Mathematics

1 answer:

Whitepunk [10]3 years ago

7 0

Answer:

the hot-holding temperature threshold is 135 degrees Fahrenheit

Step-by-step explanation:

the hot-holding temperature threshold is 135 degrees Fahrenheit

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Where do i graph?<br> please send picture of your own for me to copy

melomori [17]

Answer:

Step-by-step explanation:

Compound inequality has been given as,

12(2x - 10) + 24 ≥ 48 Or 6x + 15 - 9x ≥ 6

By simplifying it further,

12(2x - 10) + 24 ≥ 48

$\frac{12(2x - 10)}{12}+\frac{24}{12}\geq \frac{48}{12}$

(2x - 10) + 2 ≥ 4

(2x - 10) + 2 - 2 ≥ 4 - 2

2x - 10 ≥ 2

2x - 10 + 10 ≥ 2 + 10

2x ≥ 12

$\frac{2x}{2}\geq \frac{12}{2}$

x ≥ 6

6x + 15 - 9x ≥ 6

(6x - 9x) + 15 ≥ 6

(-3x) + 15 ≥ 6

-3x + 15 - 15 ≥ 6 - 15

-3x ≥ -9

3x ≤ 9

x ≤ 3

We have to plot the inequality on a number line

x ≥ 6 Or x ≤ 3

7 0

2 years ago

Does anyone know how he got from step 1 to step 2??????????

padilas [110]

9514 1404 393

Explanation:

Both sides of the equation are squared.

$\dfrac{x-12}{4}=\sqrt{x} \qquad\text{given}\\\\ \left(\dfrac{x-12}{4}\right)^2=x \qquad\text{square both sides}\\\\ \left(\dfrac{x}{4}-3\right)^2=x \qquad\text{divide out the fraction}\\\\ \dfrac{x^2}{4^2}-\dfrac{6}{4}x+9=x \qquad\text{$(a-b)^2=a^2-2ab+b^2$}\\\\\dfrac{x^2}{16}-\dfrac{5x}{2}+9=0 \qquad\text{subtract $x$}$