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3 years ago

If there are 16oz in a pound how many oz are in 10 pounds

2 answers:

ozzi3 years ago

5 0

160 oz in 10 pounds. You will have to multiply 10 and 16. You take the number of pounds and multiply it by 16 because 1:16 is the pound:oz ratio.

liq [111]3 years ago

4 0

160oz. This is because, knowing that there are 16oz in one pound, you can multiply 16 by how many pounds you have to get the oz measurement. In this problem, we multiplied 16 by 10, getting 160oz.

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You're given a fraction in simplest form the numerator is not a zero when you write the fraction as a decimal it is a repeating

oksano4ka [1.4K]

The denominator can be 3 if the numerator is 1

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3 years ago

In three more years Miguel's grandfather will be six times as old as Miguel was last year. When Miguel's grandfather present age

lora16 [44]

"In three more years,Miguel's grandfather will be six times as old as Miguel was last year. When Miguel's present age is added to his grandfather's present age, the total is 68. How old is each one now?"

Miguel is 11 years old and his grandfather is 57 years old.
Last year Miguel was 10. In three more years his grandfather would be 60. 60/6=10. 11+57=68

7 0

3 years ago

A recent study found that the average length of caterpillars was 2.8 centimeters with a

pogonyaev

Using the normal distribution, it is found that there is a 0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean $\mu$ and standard deviation $\sigma$ is given by:

$Z = \frac{X - \mu}{\sigma}$

The z-score measures how many standard deviations the measure is above or below the mean.

Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

In this problem, the mean and the standard deviation are given, respectively, by:

$\mu = 2.8, \sigma = 0.7$ .

The probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters is <u>one subtracted by the p-value of Z when X = 4</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{4 - 2.8}{0.7}$

Z = 1.71

Z = 1.71 has a p-value of 0.9564.

1 - 0.9564 = 0.0436.

0.0436 = 4.36% probability that a randomly selected caterpillar will have a length longer than (greater than) 4.0 centimeters.

More can be learned about the normal distribution at brainly.com/question/24663213

#SPJ1

4 0

2 years ago

Find the x- and y-intercepts of the graph of the linear equation −x+8y=4.

Ulleksa [173]

X intercept: (-4,0)
y intercept: (0,1/2)

x-intercept is when y = 0
-x+8(0)=4
-x+0=4
x=-4

y-intercept is when x = 0
-(0)+8y=4
8y=4
y=4/8=1/2

6 0

2 years ago

PLS SOLVE THIS EQUATION ASAP!!!

Alex777 [14]

90 degrees plus 49 degrees is 139 degrees 180 degrees minus 139 degrees = 41 degrees

90+49=139

180-139= 41

answer 41 degrees

4 0

3 years ago

Read 2 more answers