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3 years ago

How do you write: One third of the opposite of a number is less than 12?

Mathematics

1 answer:

Romashka [77]3 years ago

5 0

-1/3n = -12 is the way you write it

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Lester rents his vacation home for 6 months and lives in the home during the other 6 months of 2018. The gross rental income fro

zepelin [54]

Answer:

$ 500

Step-by-step explanation:

Data provided:

Gross rental income from the home = $ 4,500

Real estate taxes for the year = $ 800

Interest per year = $ 3,000

Utilities and maintenance expenses = $ 2,200

Depreciation expense = $ 4,000

Now, for 6 months

Real estate taxes for the year = $ 800 × 0.5 = $ 400 (0.5 as the for half a year i.e 6 months)

Interest per year = $ 3,000 × 0.5 = $ 1500

Utilities and maintenance expenses = $ 2,200 × 0.5 = $ 1,100

Depreciation expense = $ 4,000 × 0.5 = $ 2,000

Thus,

Total expenses for 6 months = $ 400 + $ 1500 + $ 1,100 + $ 2,000 = $ 5000

Therefore,

Net loss from renting his vacation home = Total expenses - Gross income

Net loss from renting his vacation home = $ 5000 - $ 4500 = $ 500

6 0

3 years ago

Here it is the better quality question

My name is Ann [436]

Answer:if your still doing this comment and I will try helping

Step-by-step explanation:

6 0

3 years ago

For number five I need help plz help

bonufazy [111]

1. 1000 2. 0.001. hope this helps.

6 0

3 years ago

1. The amount of extension in an elastic spring varies directly as the weight hung on it. If a weight of 150 gm produces an exte

gregori [183]

Answer:

900 g

Step-by-step explanation:

let e be extension and w be weight

given e varies directly as w then the equation relating them is

e = kw ← k is the constant of variation

to find k use the condition w = 150 , e = 2.9 , then

2.9 = 150k ( divide both sides by 150 )

$\frac{2.9}{150}$ = k , that is

k = $\frac{29}{1500}$

e = $\frac{29}{1500}$ w ← equation of variation

when e = 17.4 , then

17.4 = $\frac{29}{1500}$ w ( multiply both sides by 1500 )

26100 = 29w ( divide both sides by 29 )

900 = w

3 0

3 years ago

Evaluate C_n.xP^xQn-x For the given n=7, x=2, p=1/2

r-ruslan [8.4K]

Answer:

The value of given expression is $\frac{21}{128}$ .

Step-by-step explanation:

Given information: n=7, x=2, p=1/2

$q=1-p=1-\frac{1}{2}=\frac{1}{2}$

The given expression is

$C(n,x)p^xq^{n-x}$

It can be written as

$^nC_xp^xq^{n-x}$

Substitute n=7, x=2, p=1/2 and q=1/2 in the above formula.

$^7C_2(\frac{1}{2})^2(\frac{1}{2})^{7-2}$

$\frac{7!}{2!(7-2)!}(\frac{1}{2})^2(\frac{1}{2})^{5}$

$\frac{7!}{2!5!}(\frac{1}{2})^{2+5}$

$\frac{7\times 6\times 5!}{2\times 5!}(\frac{1}{2})^{2+5}$

$21(\frac{1}{2})^{7}$

$\frac{21}{128}$

Therefore the value of given expression is $\frac{21}{128}$ .

7 0

3 years ago